(a)
Interpretation:
The balanced dissociation reaction equation and the associated equilibrium constant expression for the given processes has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its
For a general reaction,
The concentration of solids and pure liquids do not change, so their concentration terms are not included in the equilibrium constant expression.
(b)
Interpretation:
Among the given compounds the one that is more soluble has to be given along with explanation.
(c)
Interpretation:
Among the given compounds the one that is less soluble has to be given along with explanation.
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Chapter 12 Solutions
OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:
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- Write a chemical equation for an equilibrium system that would lead to the following expressions (ad) for K. (a) K=(PH2S)2 (PO2)3(PSO2)2 (PH2O)2 (b) K=(PF2)1/2 (PI2)1/2PIF (c) K=[ Cl ]2(Pcl2)[ Br ]2 (d) K=(PNO)2 (PH2O)4 [ Cu2+ ]3[ NO3 ]2 [ H+ ]8arrow_forwardWhat is the law of mass action? Is it true that the value of K depends on the amounts of reactants and products mixed together initially? Explain. Is it true that reactions with large equilibrium constant values are very fast? Explain. There is only one value of the equilibrium constant for a particular system at a particular temperature, but there is an infinite number of equilibrium positions. Explain.arrow_forward5.49. Consider the following equilibrium: What is the effect on the equilibrium of each of the following changes? (You may need to calculate some standard enthalpy or Gibbs energy changes to answer these.) (a) The pressure is increased by decreasing the volume. (b) The temperature is decreased. (c) The pressure is increased by the addition of nitrogen gas, .arrow_forward
- Consider the system 4NH3(g)+3O2(g)2N2(g)+6H2O(l)H=1530.4kJ (a) How will the concentration of ammonia at equilibrium be affected by (1) removing O2(g)? (2) adding N2(g)? (3) adding water? (4) expanding the container? (5) increasing the temperature? (b) Which of the above factors will increase the value of K? Which will decrease it?arrow_forwardimage solutions step by steparrow_forwardThe solubility of iron(II) hydroxide, Fe(OH)2, is 1.43×10–3 gram per liter at 25 °C. (a) Write a balanced equation for the solubility equilibrium. (b) Write the expression for the solubility product constant, Ksp, and calculate its value.arrow_forward
- 3. When combined in a closed vessel, hydrogen gas and iodine gas will form hydrogen iodide gas until an equilibrium position is reached. m MO (a) Write a balanced equation for this chemical reaction system. (b) Suppose you carry out an investigation starting with a 2.0 L flask containing 0.45 mol of hydrogen iodide. Predict how the concentrations of the gases will change as the system reaches equilibrium. (c) In a second experiment, the concentration of each of the gases was monitored (Figure 9). Complete an ICE table for the reaction. Reaction Progress 8.0 t= 200 °C 7.0 (H(g) 6.0 5.0 4.0 3.0 - [H(9)] 2.0 1.0 0.0 Time Figure 9 Concentration (mol/L)arrow_forwardWrite the equilibrium constant expression, K, for the following reaction taking place in dilute aqueous solution. NO, (aq) + H20 ()=HNO, (aq) + OH¯ (aq) K =arrow_forwardConsider the equilibrium system described by the chemical reaction below. If 8.98 × 104 moles of KOH(aq), 8.98 × 104 moles of HCN(aq), and 0.0500 moles of KCN(aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K, what is the value of K of the reaction at this temperature? KCN(aq) + H,O(I) = KOH(aq) + HCN(aq) [8.98 × 104] K || [0.0500] [1.80 x 10-²] 1 [8.06 x 10-7] 1.80 x 10-² RESET 1.61 x 10-5arrow_forward
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