The graph of exercise 45 is to be considered to answer the question. The concentration of A is to be calculated for the given time. The first three half-lives is to be calculated for this experiment. Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations. To determine : The concentration of A after 9 s .
The graph of exercise 45 is to be considered to answer the question. The concentration of A is to be calculated for the given time. The first three half-lives is to be calculated for this experiment. Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations. To determine : The concentration of A after 9 s .
Interpretation: The graph of exercise
45 is to be considered to answer the question. The concentration of
A is to be calculated for the given time. The first three half-lives is to be calculated for this experiment.
Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.
To determine: The concentration of
A after
9s.
(b)
Interpretation Introduction
Interpretation: The graph of exercise
45 is to be considered to answer the question. The concentration of
A is to be calculated for the given time. The first three half-lives is to be calculated for this experiment.
Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.
To determine: The first three half lives of the given experiment.
Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below.
Find the following:
(a) The no. of protons corresponding to each signal in the spectra
(6) Give the structure of the compound and assign the signals to each
proton in the compound.
a
70.2
Integration Values
C5H10O2
b
47.7
C
46.5
d
69.5
3.6 3.5
3.4 3.3 3.2 3.1 3.0
2.9 2.8
2.7
2.6 2.5
2.4 2.3 2.2 2.1 2.0
Chemical Shift (ppm)
1.9
1.8
1.7 1.6
1.5
1.4 1.3 1.2
1.1 1.0
0.9 0.8
Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below.
Answer the following:
(a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure
of the molecule below.
(b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible.
complex splitting patterns assuming J values are not similar.
там
Br
22
2
3
6
4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0
Chemical Shift (ppm)
ra.
Br
2
3
6
6
2.5
2.4
2.3
2.2
2.1
2.0
1.9
1.8
1.7
1.6
1.5
1.4
1.3
1.2
1.1
1.0
0.9
0.8
Chemical Shift (ppm)
2
2
Br
7.3
7.2
7.1
7.0 6.9
6.7 6.6 6.5
6.4
6.3
6.2
6.1
6.0
Chemical Shift (ppm)
5.9
5.8 5.7
5.5 5.4 5.3 5.2
5.0 4.9
1600°
1538°C
1493°C
In the diagram, the letter L indicates
that it is a liquid. Indicate its
components in the upper region
where only L is indicated.
The
iron-iron carbide phase
diagram.
Temperature (°C)
1400
8
1394°C
y+L
1200
2.14
y, Austenite
10000
912°C
800a
0.76
0.022
600
400
(Fe)
a, Ferrite
Composition (at% C)
15
1147°C
a + Fe3C
2
3
Composition (wt% C)
L
2500
4.30
2000
y + Fe3C
727°C
1500
Cementite (Fe3C)
1000
4
5
6
6.70
Temperature (°F)