Chapter 12, Problem 1SAQ

Interpretation Introduction

Introduction: Nonpolar compounds are soluble in nonpolar solvents.

Answer to Problem 1SAQ

Correct answer: The nonpolar compound is ${\text{CBr}}_4$.

There fore, option (b) is correct.

Explanation of Solution

Justify reasons for the correct statement:

Octane is a nonpolar solvent. A compound or solute that is nonpolar in nature can readily dissolve in octane. Out of the mentioned compounds, ${\text{CBr}}_4$ is nonpolar in nature. So, it is readily soluble in octane.

Hence, option (b) is correct.

Justify reasons for the incorrect statements:

The compounds ${\text{CH}}_3\text{OH}$, ${\text{H}}_2\text{O}$, and ${\text{NH}}_3$ are polar in nature. These are not soluble in nonpolar octane.

Hence, options (a), (d), and (c) are incorrect.

Conclusion

The compound ${\text{CBr}}_4$ is soluble in octane.