Final volume of CH 4 gas if temperature is changed from − 25 ° C to 298 K has to be determined. Concept Introduction: Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure. Mathematically relation for Charles’ law is as follows: V ∝ T Or, V 1 T 1 = V 2 T 2 Here, T 1 is initial temperature. T 2 is final temperature. V 1 is initial volume. V 2 is final volume.

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Answer 1

Question

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

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Answer 2

Question

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

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Answer 3

Question

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

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Answer 4

Question

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

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Answer 5

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

Answer 6

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

Answer 7

Chapter 12, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 298 K has to be determined.

Concept Introduction:

Charles’ law represents direct relation of volume of fixed mass of ideal gas with its temperature at fixed pressure.

Mathematically relation for Charles’ law is as follows:

V∝T

Or,

V1T1=V2T2

Here,

T1 is initial temperature.

T2 is final temperature.

V1 is initial volume.

V2 is final volume.

Answer 8

(a)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.690 L.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Substitute 575 mL for V1, 248 K for T1, and 298 K for T2 in equation (1).

V2=((575 mL)(298 K)248 K)(1 L103 mL)=0.690 L

Hence final volume of CH4 gas is 0.690 L.

Answer 13

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

Answer 14

(b)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.633 L.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert degree Fahrenheit to Celsius is as follows:

T(°C)=59(T(°F)−32) (2)

Substitute 32 °F in equation (2).

T(°C)=59(32 °F−32)=0 °C

Conversion factor to convert 0 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=0 °C+273=273 K

Substitute 575 mL for V1, 248 K for T1, and 273 K for T2 in equation (1).

V2=((575 mL)(273 K)248 K)(1 L103 mL)=0.633 L

Hence final volume of CH4 gas is 0.633 L.

Answer 20

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

Answer 21

(c)

Interpretation Introduction

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).

Answer 22

(c)

Expert Solution

Answer to Problem 14PE

Final volume of CH4 gas is 0.737 L.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Expression to calculate final volume of gas is as follows:

V2=V1T2T1 (1)

Conversion factor to convert −25 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=−25 °C+273=248 K

Conversion factor to convert 45 °C to Kelvin is as follows:

T(K)=temperature in celsius+273=45 °C+273=318 K

Substitute 575 mL for V1, 248 K for T1, and 318 K for T2 in equation (1).

V2=((575 mL)(318 K)248 K)(1 L103 mL)=0.737 L

Hence final volume of CH4 gas is 0.737 L.

Answer 27

Ch. 12.1 - Prob. 12.1P Ch. 12.2 - Prob. 12.2P Ch. 12.3 - Prob. 12.3P Ch. 12.5 - Prob. 12.4P Ch. 12.5 - Prob. 12.5P Ch. 12.5 - Prob. 12.6P Ch. 12.6 - Prob. 12.7P Ch. 12.6 - Prob. 12.8P Ch. 12.7 - Prob. 12.9P Ch. 12.8 - Prob. 12.10P

Answer to Problem 14PE

Explanation of Solution

Interpretation: Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 14PE

Explanation of Solution

Interpretation: Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 14PE

Explanation of Solution

Want to see more full solutions like this?

Chapter 12 Solutions

Interpretation:

Final volume of CH4 gas if temperature is changed from −25 °C to 32 °F has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

Final volume of CH4 gas if temperature is decreased from −25 °C to 45 °C has to be determined.

Concept Introduction:

Refer to part (a).