Given: File size = 2048 bytes Payload size = 512 bytes Given that systems are running in IPv4. We know that: Size of TCP header = 20 bytes Size of IP header = 20 bytes Total size = 40 bytes overhead per segment The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total. So totally 2208 bytes will be sent by 4 segments.

Question

Want to see the full answer?

Answer 1

Question

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

List down the strenghts and weaknesses of your team project for Capsim Simulation? Explan.

Capsim Team PowerPoint Presentations - Slide Title: Key LearningsWhat were the key learnings that you discovered as a team through your Capsim simulation?

Write the SQL code that permits to implement the tables: Student and Transcript. NB: Add the constraints on the attributes – keys and other.

Answer 2

Question

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Answer 6

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

Answer 7

Chapter 12, Problem 12E

a.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (40 + 512) × 4 = 2208 bytes in total.

So totally 2208 bytes will be sent by 4 segments.

Answer 8

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Answer 9

b.

Program Plan Intro

Given:

File size = 2048 bytes

Payload size = 512 bytes

Given that systems are running in IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 4 segments each segment contains 512 bytes. So, there are (60 + 512) × 4 = 2288 bytes in total.

So totally 2288 bytes will be sent by 4 segments.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 12 - Prob. 1RETC Ch. 12 - Prob. 2RETC Ch. 12 - Prob. 3RETC Ch. 12 - Prob. 4RETC Ch. 12 - Prob. 5RETC Ch. 12 - Prob. 6RETC Ch. 12 - Prob. 7RETC Ch. 12 - Prob. 8RETC Ch. 12 - Prob. 9RETC Ch. 12 - Prob. 10RETC

Want to see the full answer?

Chapter 12 Solutions