The acid with larger Ka value should be detected and reason of larger value should be explained. Concept Introduction: The value of K a , gives the dissociation constant for an acid. Hence, stronger the value of acid, more will be dissociation and so larger will be the value of K a .
The acid with larger Ka value should be detected and reason of larger value should be explained. Concept Introduction: The value of K a , gives the dissociation constant for an acid. Hence, stronger the value of acid, more will be dissociation and so larger will be the value of K a .
Solution Summary: The author explains the titration curve for acid A and B, where the amount of base solution is stoichiometrically enough to neutralize the sample.
The acid with larger Ka value should be detected and reason of larger value should be explained.
Concept Introduction:
The value of Ka, gives the dissociation constant for an acid. Hence, stronger the value of acid, more will be dissociation and so larger will be the value of Ka.
(b)
Interpretation Introduction
Interpretation:
pH should be estimated for each acid and difference between their values should be explained.
Concept Introduction:
Equivalence point is the point of titration curve where, the amount of titrant added is stoichiometrically enough to neutralize the amount of sample. It is detected at halfway of the steep curve.
The pH at this point will be the equivalent pH.
(c)
Interpretation Introduction
Interpretation:
If volume of acids A and B are taken equal then, acid with higher initial concentration should be determined.
Concept Introduction:
pH gives the concentration of H+ ions, which can explain the concentration of the acid.pH=−log[H+]
CHEM2323
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Tt
PS CH03
Draw and name all monobromo derivatives of pentane, C5H11Br.
Problem 3-33
Name:
Draw structures for the following:
(a) 2-Methylheptane
(d) 2,4,4-Trimethylheptane
Problem 3-35
(b) 4-Ethyl-2,2-dimethylhexane
(e) 3,3-Diethyl-2,5-dimethylnonane
(c) 4-Ethyl-3,4-dimethyloctane
2
(f) 4-Isopropyl-3-methylheptane
KNIE>
Problem 3-42
Consider 2-methylbutane (isopentane). Sighting along the C2-C3 bond:
(a) Draw a Newman projection of the most stable
conformation.
(b) Draw a Newman projection of the least stable
conformation.
Problem 3-44
Construct a qualitative potential-energy diagram for rotation about the C-C bond of 1,2-dibromoethane.
Which conformation would you expect to be most stable? Label the anti and gauche conformations of 1,2-
dibromoethane.
Problem 3-45
Which conformation of 1,2-dibromoethane (Problem 3-44) would you expect to have the largest dipole
moment? The observed dipole moment of 1,2-dibromoethane is µ = 1.0 D. What does this tell you about the
actual conformation of the molecule?
Chapter 12 Solutions
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