Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
9th Edition
ISBN: 9781305968707
Author: Spencer L. Seager
Publisher: Brooks Cole
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Chapter 12, Problem 12.38E

What type of hybridized orbital is present on carbon atoms bonded by a triple bond? How many of these hybrid orbitals are on each carbon atom?

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Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…
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Chapter 12 Solutions

Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version

Ch. 12 - Prob. 12.11ECh. 12 - Prob. 12.12ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - What type of orbital overlaps to form a pi bond in...Ch. 12 - Prob. 12.15ECh. 12 - Explain the difference between geometric and...Ch. 12 - Draw structural formulas and give IUPAC names for...Ch. 12 - Prob. 12.18ECh. 12 - Which of the following alkenes can exist as...Ch. 12 - Draw structural formulas for the following:...Ch. 12 - Prob. 12.21ECh. 12 - In what ways are the physical properties of...Ch. 12 - Prob. 12.23ECh. 12 - Prob. 12.24ECh. 12 - Complete the following reactions. Where more than...Ch. 12 - Prob. 12.26ECh. 12 - Prob. 12.27ECh. 12 - What reagents would you use to prepare each of the...Ch. 12 - What is an important commercial application of...Ch. 12 - Prob. 12.30ECh. 12 - Terpin hydrate is used medicinally as an...Ch. 12 - Prob. 12.32ECh. 12 - Prob. 12.33ECh. 12 - Prob. 12.34ECh. 12 - Prob. 12.35ECh. 12 - Much of todays plumbing in newly built homes is...Ch. 12 - Prob. 12.37ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - How many sigma bonds and how many pi bonds make up...Ch. 12 - Prob. 12.40ECh. 12 - Explain why geometric isomerism is not possible in...Ch. 12 - Give the common name and major uses of the...Ch. 12 - Describe the physical and chemical properties of...Ch. 12 - Prob. 12.44ECh. 12 - Prob. 12.45ECh. 12 - Prob. 12.46ECh. 12 - Prob. 12.47ECh. 12 - Prob. 12.48ECh. 12 - Limonene, which is present in citrus peelings, has...Ch. 12 - A disubstituted cycloalkane such as a exhibits...Ch. 12 - Prob. 12.51ECh. 12 - Prob. 12.52ECh. 12 - Give an IUPAC name for the following as...Ch. 12 - Give an IUPAC name for the following as...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Prob. 12.59ECh. 12 - Write structural formulas for the following:...Ch. 12 - Prob. 12.61ECh. 12 - Prob. 12.62ECh. 12 - Prob. 12.63ECh. 12 - Prob. 12.64ECh. 12 - Prob. 12.65ECh. 12 - Prob. 12.66ECh. 12 - Prob. 12.67ECh. 12 - Prob. 12.68ECh. 12 - Prob. 12.69ECh. 12 - Prob. 12.70ECh. 12 - Prob. 12.71ECh. 12 - Prob. 12.72ECh. 12 - Prob. 12.73ECh. 12 - Prob. 12.74ECh. 12 - Prob. 12.75ECh. 12 - Prob. 12.76ECh. 12 - Prob. 12.77ECh. 12 - Prob. 12.78ECh. 12 - Prob. 12.79ECh. 12 - Prob. 12.80ECh. 12 - Prob. 12.81ECh. 12 - Prob. 12.82ECh. 12 - Prob. 12.83ECh. 12 - The compound CH2=CHCH2CH2CH3 is an example of: a....Ch. 12 - The correct structural for ethyne is: a. HC=CH b....Ch. 12 - Prob. 12.86E
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