(a) To determine: The bond in polyvinyl chloride that have the lowest average bond enthalpy. Solution: The C − Cl bond has lowest bond enthalpy. Explanation: Polyvinyl chloride have C − C , C − H and C − Cl bonds. Their bond enthalpies are: C − C bond = 348 kJ/mol C − H bond = 413 kJ/mol C − Cl bond = 328 kJ/mol Therefore, the bond with lowest average bond enthalpy is C − Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy. Conclusion: The C − Cl bond has lowest bond enthalpy.

Question

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Answer 1

Question

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Expert Solution & Answer

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Answer 2

Question

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Expert Solution & Answer

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Answer 3

Question

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Expert Solution & Answer

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See solution

Answer 5

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Answer 6

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

Answer 7

Chapter 12, Problem 122IE

Interpretation Introduction

(a)

To determine:

The bond in polyvinyl chloride that have the lowest average bond enthalpy.

Solution:

The C−Cl bond has lowest bond enthalpy.

Explanation:

Polyvinyl chloride have C−C , C−H and C−Cl bonds. Their bond enthalpies are:

C−C bond =348 kJ/mol
C−H bond =413 kJ/mol

C−Cl bond =328 kJ/mol

Therefore, the bond with lowest average bond enthalpy is C−Cl bond. The electronegativity difference between carbon and chlorine is high, therefore the bond is readily broken. Hence it has lowest bond enthalpy.

Conclusion:

The C−Cl bond has lowest bond enthalpy.

Answer 8

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

Answer 9

(b)

Interpretation Introduction

To determine:

The bond which is most likely to break first.

Answer 10

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Answer 11

(c)

Interpretation Introduction

To determine:

The overall enthalpy change for converting PVC to diamond.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 12.3 - The following diagram shows the combination...Ch. 12.3 - 3.3 The following diagram represents the...Ch. 12.5 - 3.4 The following diagram represents the...Ch. 12.5 - Glycine, an amino acid used by organisms to make...Ch. 12.7 - The following diagram represents a...Ch. 12.7 - 3.7 Nitrogen (N2) and hydrogen (H2) react to form...Ch. 12.7 - 3.8 Nitrogen monoxide and oxygen react to form...Ch. 12.7 - Write "true" or "false" for each statement. a. We...Ch. 12 - Determine the empirical and molecular formulas of...Ch. 12 - a. Combustion analysis of toluene, a common...

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To determine:

The bond which is most likely to break first.

To determine:

The overall enthalpy change for converting PVC to diamond.

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Chapter 12 Solutions

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To determine: The bond which is most likely to break first.

To determine: The overall enthalpy change for converting PVC to diamond.

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Chapter 12 Solutions

To determine:

The bond which is most likely to break first.

To determine:

The overall enthalpy change for converting PVC to diamond.