Explanation Given information: Given values are: V i = 0.2 mV V f b = 0.195 mV R i = 20 kΩ R o = 10 kΩ I o = 5 mA Given circuit is shon below. Calculation: Value of A g f is : A g f = I o V i A g f = 5 mA 0.2 mV A g f = 25 Value of ß z is: β z = V f b I o β z = 0.195 mV 5 mA β z = 0.039 Value of voltage V E is − V i = V E + V f b V E = V i − V f b V E = ( 0.2 − 0

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

4th Edition

ISBN: 9781266368622

Author: NEAMEN

Publisher: MCG

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Chapter 12, Problem 12.24P

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Values of different parameter of ideal series-series amplifier.

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Chapter 12, Problem 12.23P

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Chapter 12 Solutions

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

Ch. 12 - (a) The open-loop gain of an amplifier is A=5104...Ch. 12 - (a) Consider a general feedback system with...Ch. 12 - (a) A feedback amplifier has an open-loop...Ch. 12 - (a) Consider the circuit shown in Figure...Ch. 12 - (a) The closed-loop gain of a feedback amplifier...Ch. 12 - The gain factors in a feedback system are A=5105...Ch. 12 - Prob. 12.3TYU Ch. 12 - An ideal series-shunt feedback amplifier is shown...Ch. 12 - Consider the ideal shunt-series feedback amplifier...Ch. 12 - An ideal series-series feedback amplifier is shown...

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Values of different parameter of ideal series-series amplifier.

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Values of different parameter of ideal series-series amplifier.

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