Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 12, Problem 12.22P
To determine
Find the pore pressure at failure for the unconfined compression test.
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Undisturbed samples from a normally consolidated clay layer were collected during a subsoil exploration .Drained triaxial tests showed that the effective friction angle was ? ′ = 25°. The unconfined compressive strength, ??, of a similar specimen was found to be 133 KN/m2 . Find the pore pressure at failure for the unconfined compression test.
2- A three-axis compression test on a clay sample
that is comprehensive and normal up to a stress
of 300 kPa and a specific volume of 2
Consolidated is done, The values of q and
volumetric strain are measured at axial strain, 0, 2
and 10 percent (failure) . The value of N is equal
to 3 and A is equal to 0.2. Graph of all-round
stress on initial all-round stress
Draw the initial all-round stress in terms of
section
A consolidated undrained triaxial test was
performed on a normally consolidated clay
with a critical state friction angle of 230. After
an initial isotropic consolidation at a cell
pressure of 50 kPa, drainage was turned off,
the cell pressure was increased to 85 kPa,
and the sample was loaded to ultimate
conditions. A pore pressure of 55 kPa was
measured at ultimate state. What value of
major principal total stress was measured at
the ultimate state?
Chapter 12 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- Q3: Undisturbed samples from a normally consolidated clay layer were collected during a field exploration program. Drained triaxial tests showed that the effective friction angle Ø'=28°. The unconfined compressive strength, qu, of a similar specimen was found to be 148 kN/m2. Determine the pore pressure at failure for the unconfined compression test.arrow_forwardThe effective strength parameters for a clay are known to be cʹ = 15kPa and φʹ = 29°. A UU triaxial test and CUtriaxial test were performed on identical saturated samples of the same clay. In both cases, the cell pressure was 100 kPa. In the UU test, the deviator stress at failure was 98 kPa, and in the CU test, the deviator stress at failure was 264 kPa. Find:•The undrained shear strength, su, of the specimen from the UU test•The pore pressure in the specimen at failure in the UU test.•The value of the Skempton parameter A̅ f from the CU testarrow_forwardA CU triaxial compression test was performed on saturated sand at a cell pressure of 100 kPa. The ultimate deviator stress was 350 kPa and the pore pressure at the peak stress was 40 kPa (suction). Estimate the total and effective stress shear strength parameters.arrow_forward
- A consolidated-undrained test determines that the shear strength of a normally consolidated clay is given by τf = σ’tan 27o. The confining pressure is 150 kPa, and deviator stress at failure is 120 kPa.• Find the consolidated-undrained friction angle• Pore water pressure developed in the specimen at failureFinal answer should be in 3 decimal places.arrow_forwardA drained triaxial compression test on a saturated clay yielded the effective shear strength parameters as c' = 15 kPa and o'= 22°. %3D Consolidated Undrained triaxial test on an identical sample of this clay at a cell pressure of 200 kPa developed a pore water pressure of 150 kPa at failure. The deviator stress (expressed in kPa) at failure isarrow_forwardA clay specimen with drained shear strength parameters of c'=5 kPa and Φ=320 is consolidated under all around pressure of 140 kPa.The specimen was then loaded axially to failure under undrained condition and failed when the principal stress diffrences reached 60 kPa.Calculate the pore pressure(u) and the pore pressure coefficient D(=A*B=Δu/Δσv) of the clay.arrow_forward
- 2- A three-axis compression test has been performed on the clay sample, which has been comprehensively and normally strengthened to a stress of 300 kPa and a specific volume of 200. The values of q and volumetric strain are measured at axial strain of 0, 2 and percent (rupture). The value of N is equal to 300 and Landa is equal to 0.2. Draw a diagram of all- round stress on the initial all-round stress in terms of slicing on the initial all-round stress:.arrow_forwardPlease answer 12.20arrow_forward• In consolidated-drained triaxial test on a normally consolidated clay, the specimen failed at a deviator stress of 124 KN/sq.m. If the effective stress friction angle is known to be 31°, what was the effective confining pressure at failure?arrow_forward
- A series of previous CD tests conducted on a NC clay has established that the ultimate effective friction angle of the clay is 300. Now a CU test is conducted on this soil with an effective cell pressure of 100 kPa. The specimen fails at a deviatoric stress of 100 kPa. Estimate the pore pressure at failure. Given: σ3f′=Kaσ1f′whereKa=1−sinϕ1+sinϕ Please do fast .... ASAP Fastarrow_forwardA consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The specimen was consolidated under a cell pressure of 100 kPa and back pressure of 30 kPa. The axial deviatoric stress was increased very slowly to failure, so that there was no excess pore water pressure developed during the shearing. The specimen failed under a deviatoric stress of 130 kPa. The back pressure of 30 kPa was maintained throughout the test. (i) What is the friction angle in terms of effective stresses? (ii) What are the shear stress and normal stress acting on the failure plane? Solution fast pleasearrow_forwardPlease solve with in 40 minutesarrow_forward
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