
Interpretation:
The given questions based upon the
Concept introduction: Isotactic polypropylene has highest melting point and crystallinity while atactic polypropylene has lowest crystallinity and melting point. The difference is due to arrangement of substituents in the respective
(a)
To determine:
The hybridization of orbitals at each carbon atom in polyethylene and the angles between the bonds.
(b)
To determine:
The structure of polypropylene in which the methyl groups lie on the same side of the plane of paper; one in which methyl groups lie on alternating sides of plane; the structure in which methyl groups are randomly distributed on the either side; the form that will have highest crystallinity and melting point; and which has the lowest crystallinity and melting point and explanation in terms of intermolecular interactions and molecular shapes.
(i)
To determine:
The structure of polypropylene in which the methyl groups lie on the same side of the plane of paper.
(ii)
To determine:
The structure of polypropylene in which the methyl groups lie on alternating sides of plane.
(iii)
To determine:
The structure in which methyl groups are randomly distributed on the either side; the form that will have highest crystallinity and melting point; and which has the lowest crystallinity and melting point and explanation in terms of intermolecular interactions and molecular shapes.
(c)
To determine:
An explanation for the difference between polypropylene and polyester or cotton in terms of intermolecular interactions with water.

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Chapter 12 Solutions
Chemistry the Central Science 13th Edition Custom for Lamar University
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- Briefly describe the synthesis mechanism of barbituric acid from the condensation of urea with a β-diketone.arrow_forwardGiven the hydrazones indicated, draw the structures of the enamines that can be formed. Indicate the most stable enamine (explain). C6H5 C6H5 H C6H5 Harrow_forward4. Propose a Synthesis for the molecule below. You may use any starting materials containing 6 carbons or less (reagents that aren't incorporated into the final molecule such as PhзP do not count towards this total, and the starting material can have whatever non-carbon functional groups you want), and any of the reactions you have learned so far in organic chemistry I, II, and III. Your final answer should show each step separately, with intermediates and conditions clearly drawn.arrow_forward
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