(a)
Interpretation:
The solvent that has stronger interactions with the
Concept introduction:
Intermolecular forces operate between the molecules so changes with change in the phase and effects with physical properties of the substance. In intermolecular forces, the bond is formed between two molecules with partial charges that are present relatively far away from each other.
Viscosity is the quantity that determines the resistance of the liquid to flow. Both liquids and gases can flow but gases have high viscosity than liquids. Viscosity is directly related to the intermolecular forces and therefore increases with increase in the intermolecular forces.
The formula to calculate the intrinsic viscosity is as follows:
Here,
(b)
The intrinsic viscosity of benzene is to be calculated. Also, the use of intrinsic viscosity in a given solvent to determine the molar mass of any sample of that polymer is to be determined.
Concept introduction:
Intermolecular forces operate between the molecules so changes with change in the phase and effects with physical properties of the substance. In intermolecular forces, the bond is formed between two molecules with partial charges that are present relatively far away from each other.
Viscosity is the quantity that determines the resistance of the liquid to flow. Both liquids and gases can flow but gases have high viscosity than liquids. Viscosity is directly related to the intermolecular forces and therefore increases with increase in the intermolecular forces.
The formula to calculate the intrinsic viscosity is as follows:
Here,
(c)
The intrinsic viscosity values of a polyisobutylene sample and polystyrene sample are to be compared. Also, the solvent-polymer interactions of both the samples are to be determined.
Concept introduction:
Viscosity is the quantity that determines the resistance of the liquid to flow. Both liquids and gases can flow but gases have high viscosity than liquids. Viscosity is directly related to the intermolecular forces and therefore increases with increase in the intermolecular forces.
The formula to calculate the intrinsic viscosity is as follows:
Here,
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Chapter 12 Solutions
CHEMISTRY: THE MOLECULAR NATURE OF MATTE
- Experiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…arrow_forwardThe chemical reaction you investigated is a two-step reaction. What type of reaction occurs in each step? How did you determine your answer?arrow_forwardWhat is the relationship between the limiting reactant and theoretical yield of CO2?arrow_forward
- From your calculations, which reaction experiment had closest to stoichiometric quantities? How many moles of NaHCO3 and HC2H3O2 were present in this reaction?arrow_forward18. Arrange the following carbocations in order of decreasing stability. 1 2 A 3124 B 4213 C 2431 D 1234 E 2134 SPL 3 4arrow_forwardAcetic acid is added to DI water at an initial concentration of 10 -6 M (Ka=1.8x10-5) A. Using the "ICE" Method, what would the pH be at equilibrium? State assumptions and show your work. B. Using the simultaneous equations method, what would the pH be at equilibrium? Show your workarrow_forward
- 1. Show that the change in entropy for a fixed amount of ideal gas held at a constant temperature undergoing a volume change is given by the simple equation AS = NkB In Hint: Start with the equation M dS = du + (Œ) dv - Ž (#) an, dU du+av-dN; j=1 Why doesn't the equation for the entropy of an ideal gas depend on the strength of the intermolecular forces for the gas?arrow_forward2. Make an ice cube at 1 bar pressure by freezing an amount of liquid water that is 2 cm x 2 cm x 2 cm in volume. The density of liquid water at 0 °C is 1.000 g cm³ and the density of ice at 0 °C is 0.915 g cm³. Note that this difference in density is the reason your water pipes burst if they freeze and why you shouldn't forget to take your bottle of pop out of the freezer if you put it in there to try and cool it down faster. A. What is the work of expansion upon freezing? B. Is work done on the system or by the system?arrow_forwardI have a excitation/emission spectra of a quinine standard solution here, and I'm having trouble interpreting it. the red line is emission the blue line is excitation. i'm having trouble interpreting properly. just want to know if there is any evidence of raman or rayleigh peaks in the spectra.arrow_forward
- Give the major product of the following reaction. excess 1. OH, H₂O 1.OH H CH3CH2CH21 H 2. A.-H₂O Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.arrow_forward2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forwardci Draw the major product(s) of the following reactions: (3 pts) CH3 HNO3/H2SO4 HNO3/ H2SO4 OCH3 (1 pts)arrow_forward
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