Chapter 12, Problem 12.132P

(a)

Interpretation Introduction

Interpretation:

The pressure of water vapor in the greenhouse is to be calculated.

Concept introduction:

The ideal gas equation can be expressed as follows:

  $PV=nRT$        (1)

Here,

$P$ is the pressure.

$V$ is the volume.

$T$ is the temperature.

$n$ is the mole of the gas.

$R$ is the gas constant.

Density is defined as mass per unit volume. Mass and volume are physical quantities and the units of mass and volume are fundamental units. Density is the ratio of mass to the volume. The unit of volume is derived from the units of mass and volume. The SI unit of density is ${\text{kg/m}}^{\text{3}}$.

The formula to calculate density is,

  $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$        (2)

(b)

Interpretation Introduction

Interpretation:

The total volume of liquid water that would have to be vaporized to saturate the air is to be calculated.

Concept introduction:

The ideal gas equation can be expressed as follows:

  $PV=nRT$        (1)

Here,

$P$ is the pressure.

$V$ is the volume.

$T$ is the temperature.

$n$ is the mole of the gas.

$R$ is the gas constant.

Density is defined as mass per unit volume. Mass and volume are physical quantities and the units of mass and volume are fundamental units. Density is the ratio of mass to the volume. The unit of volume is derived from the units of mass and volume. The SI unit of density is ${\text{kg/m}}^{\text{3}}$.

The formula to calculate density is,

  $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$        (2)