Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated. Concept Introduction: Solubility of a gas in liquid is explained by Henry’s law which states – “At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.” It is expressed as, S α P Where, S = Solubility P = Partial pressure Introducing proportionality constant, S = k H P Where, k H is Henry’s constant . Solubility of a same gas at two different pressures can be calculated as, S 2 S 1 = k H P 2 k H P 1 = P 2 P 1
Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated. Concept Introduction: Solubility of a gas in liquid is explained by Henry’s law which states – “At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.” It is expressed as, S α P Where, S = Solubility P = Partial pressure Introducing proportionality constant, S = k H P Where, k H is Henry’s constant . Solubility of a same gas at two different pressures can be calculated as, S 2 S 1 = k H P 2 k H P 1 = P 2 P 1
Solution Summary: The author explains how the solubility of an unknown gas at partial pressure and temperature is calculated by Henry's law.
Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated.
Concept Introduction:
Solubility of a gas in liquid is explained by Henry’s law which states –
“At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.”
It is expressed as,
SαP
Where,
S = SolubilityP = Partial pressure
Introducing proportionality constant,
S=kHP
Where,
kH is Henry’s constant.
Solubility of a same gas at two different pressures can be calculated as,
Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.
Synthesis of Dibenzalacetone
[References]
Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below.
Question 1
1 pt
Question 2
1 pt
Question 3
1 pt
H
Question 4
1 pt
Question 5
1 pt
Question 6
1 pt
Question 7
1pt
Question 8
1 pt
Progress:
7/8 items
Que Feb 24 at
You do not have to consider stereochemistry.
. Draw the enolate ion in its carbanion form.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
⚫ Separate multiple reactants using the + sign from the drop-down menu.
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4
Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)
Chapter 12 Solutions
Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th
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