Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
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Chapter 12, Problem 10R
Why are the large diameter electrodes not used for all-position welding?
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14.10. A liquor containing 15 per cent
solids is concentrated to 55 per cent
solids in a double-effect evaporator.
operating at a pressure in the second
effect of 18 kN/m². No crystals are
formed. The flowrate of feed is 2.5 kg/
s at 375 K with a specific heat capacity
of 3.75 kJ/kg K. The boiling-point rise of
the concentrated liquor is 6 deg K and the
steam fed to the first effect is at 240 kN/
m². The overall heat transfer coefficients
in the first and second effects are 1.8 and
0.63 kW/m²K. respectively. If the heat
transfer area is to be the same in each
effect, what areas should be specified?
D
A
14.9. A forward feed double-effect vertical
evaporator, with equal heating areas in
each effect, is fed with 5 kg/s of a liquor
of specific heat capacity of 4.18 kJ/kg K.
and with no boiling point rise, so that 50
per cent of the feed liquor is evaporated.
The overall heat transfer coefficient in the
second effect is 75 per cent of that in the
first effect. Steam is fed at 395 K and the
boiling point in the second effect is 373 K.
The feed is heated by an external heater to
the boiling point in the first effect.
It is decided to bleed off 0.25 kg/s of
vapour from the vapour line to the second
effect for use in another process. If the
feed is still heated to the boiling point of
the first effect by external means, what
will be the change in steam consumption
of the evaporator unit? For the purpose of
calculation, the latent heat of the vapours
and of the steam may both be taken as
2230 kJ/kg
Ад
O
correct the shaft misalignment in a cars transmission system, determine the offset distance required to correct the shaft misalignment of 4 degrees in a rotating system. shaft diameter is 4cm.
Chapter 12 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 12 - List some factors that have led to the increased...Ch. 12 - How is FCAW similar to GMAW?Ch. 12 - What does the FCA flux provide to the weld?Ch. 12 - What are the major atmospheric contaminations of...Ch. 12 - How does slag help an FCA weld?Ch. 12 - How can FCA welding guns be cooled?Ch. 12 - Excessive drive roller pressure causes what...Ch. 12 - List the advantages that FCA welding offers the...Ch. 12 - Describe the two methods of manufacturing FCA...Ch. 12 - Why are the large diameter electrodes not used for...
Ch. 12 - How do deoxidizers remove oxygen from the weld...Ch. 12 - What do fluxing agents do for a weld?Ch. 12 - Why are alloying elements added to the flux?Ch. 12 - How does the flux form a shielding gas to protect...Ch. 12 - What are the main limitations of the rutile...Ch. 12 - Why is it more difficult to use lime-based fluxed...Ch. 12 - What benefit does adding an externally supplied...Ch. 12 - How do excessive amounts of manganese affect a...Ch. 12 - Why are elements added that cause ferrite to form...Ch. 12 - Why must a flux form a less dense slag?Ch. 12 - Referring to Table 12-5, what is the AWS...Ch. 12 - Describe the meaning of each part of the following...Ch. 12 - What does the number 316 in E316T-1 mean?Ch. 12 - What is the advantage of using an argon- CO2 mixed...Ch. 12 - Why are some slags called refractory?Ch. 12 - What can happen to slag that solidifies on the...Ch. 12 - How is the electrode extension measured?Ch. 12 - What can cause porosity in an FCA weld?Ch. 12 - What happens to water in the welding arc?Ch. 12 - What is the thin dark gray or black layer on new...Ch. 12 - Why is uniformly scattered porosity hard to detect...Ch. 12 - What cautions must be taken when chemically...
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