a) Interpretation: The actual product has to be identified. Concept introduction: Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene . An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction . When two substituents are removed from the molecule in two steps is called E1 reaction . E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene E2 elimination: Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Question

(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the reagents and product(s) for each step to receive full credit. The number of steps is provided. (OC 4) 4 steps 4 steps OH b.

Answer 1

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the reagents and product(s) for each step to receive full credit. The number of steps is provided. (OC 4) 4 steps 4 steps OH b.

LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

For the compound: C8H17NO2 Use the following information to come up with a plausible structure: 8 This compound has "carboxylic acid amide" and ether functional groups. The peaks at 1.2ppm are two signals that are overlapping one another. One of the two signals is a doublet that represents 6 hydrogens; the other signal is a quartet that represents 3 hydrogens.

Answer 2

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 3

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 4

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 5

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 6

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 7

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 8

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 9

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 10

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 11

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 12

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Ch. 11.1 - Prob. 1P Ch. 11.2 - Prob. 2P Ch. 11.2 - Prob. 3P Ch. 11.3 - Prob. 4P Ch. 11.3 - Prob. 5P Ch. 11.3 - Rank the following compounds in order of their...Ch. 11.3 - Organic solvents like benzene, ether, and...Ch. 11.4 - Prob. 8P Ch. 11.4 - Prob. 9P Ch. 11.4 - Prob. 10P

Solution Summary: The author explains that an elimination reaction is removal of two substituents in a molecule and forms alkene.

Chapter 11 Solutions