a) Interpretation: The actual product has to be identified. Concept introduction: Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene . An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction . When two substituents are removed from the molecule in two steps is called E1 reaction . E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene E2 elimination: Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Question

For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Answer 1

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Predicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.

Highlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers. OH OH OH OH OH OH

Answer 2

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 3

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 4

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 5

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 6

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 7

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 8

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 9

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 10

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 11

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 12

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Answer 23

Ch. 11.1 - Prob. 1P Ch. 11.2 - Prob. 2P Ch. 11.2 - Prob. 3P Ch. 11.3 - Prob. 4P Ch. 11.3 - Prob. 5P Ch. 11.3 - Rank the following compounds in order of their...Ch. 11.3 - Organic solvents like benzene, ether, and...Ch. 11.4 - Prob. 8P Ch. 11.4 - Prob. 9P Ch. 11.4 - Prob. 10P

Solution Summary: The author explains that an elimination reaction is removal of two substituents in a molecule and forms alkene.

Chapter 11 Solutions