Chapter 11.6, Problem 3ACYP

To determine

To calculate: To find the sum

Answer to Problem 3ACYP

The sum is $\frac{t^2-3}{t-3}$

Explanation of Solution

Given information: Expression is $\frac{t^2}{t-3}+\frac{3}{3-t}$

Calculation:

Expression is given as

  $\frac{t^2}{t-3}+\frac{3}{3-t}$

On solving the above expression,

  $\begin{array}{l}\Rightarrow \frac{t^2}{t-3}+\frac{3}{-\left(t-3\right)}\\ \Rightarrow \frac{t^2}{t-3}-\frac{3}{t-3}\\ \Rightarrow \frac{t^2-3}{t-3}\end{array}$

Conclusion:

Hence, the sum is $\frac{t^2-3}{t-3}$