Chapter 11.2, Problem 48STP

To determine

To Simplify: $\frac{2a^{2}d}{3bc}\cdot \frac{9b^{2}c}{16a{d}^2}$

Answer to Problem 48STP

  $(D)\frac{3ab}{8d}$

Explanation of Solution

Given:$\frac{2a^{2}d}{3bc}\cdot \frac{9b^{2}c}{16a{d}^2}$

  $\begin{array}{l}(A)\frac{abd}{c}\\ (B)\frac{6a}{4bd}\\ (C)\frac{ab}{d}\\ (D)\frac{3ab}{8d}\end{array}$

Given: $\frac{2a^{2}d}{3bc}\cdot \frac{9b^{2}c}{16a{d}^2}$

Solving

  $\begin{array}{l}=\frac{2a^{2}d}{3bc}\cdot \frac{9b^{2}c}{16a{d}^2}\\ =\frac{2\times a\times a\times d\times 9\times b\times b\times c}{3\times b\times c\times 16\times a\times d\times d}\\ =\frac{3ab}{8d}\end{array}$

Hence, $(D)\frac{3ab}{8d}$