Chapter 11.4, Problem 3ACYP

To determine

To solve the below expression -

  $\frac{15y^2}{4x}÷\frac{5y}{8x^3}$

Answer to Problem 3ACYP

The answer is $6x^{2}y$ .

Explanation of Solution

Given: Expression: $\frac{15y^2}{4x}÷\frac{5y}{8x^3}$

Calculation:

Given: Expression: $\frac{15y^2}{4x}÷\frac{5y}{8x^3}$

Expression can be written as:

  $\frac{15y^2}{4x}\times \frac{8x^3}{5y}$

Solving the above expression to cancel the values with the same factors, we have:

  $\begin{array}{l}\frac{15y^2}{4x}\times \frac{8x^3}{5y}\\ =\frac{15y}{4}\times \frac{8x^2}{5}\\ =\frac{3y}{1}\times \frac{2x^2}{1}\\ =6x^{2}y\end{array}$

The answer is $6x^{2}y$ .

Conclusion:

Hence, the answer is $6x^{2}y$ .