Chapter 11, Problem 17MCQ

To determine

To find: The area of the rectangle

Answer to Problem 17MCQ

The area of the rectangle is $x-2$

Explanation of Solution

Given:

  

Calculation:

The area of the rectangle is calculated below:

  $\begin{array}{l}\frac{x^2-4}{x+3}\cdot \frac{x+3}{x+2}\\ =\frac{\left(x-2\right)\left(x+2\right)}{x+3}\cdot \frac{x+3}{x+2}\\ =\frac{x-2}{1}\cdot \frac{1}{1}\\ =x-2\end{array}$

Therefore, the area of the rectangle is $x-2$

Conclusion:

Hence, the area of the rectangle is $x-2$