Chapter 11.6, Problem 26E

To determine

To calculate: The value of expression given as $anti\ln \left(-3.7612\right)$ .

Answer to Problem 26E

The value of $anti\ln \left(-3.7612\right)$ is $0.0233$ .

Explanation of Solution

Given information:

The given expression is $anti\ln \left(-3.7612\right)$ .

Formula used:

The base in natural logarithm is as $\ln x={\log }_{e}x$ .

Where the value of $e\approx 2.718$

The value of antilog can be calculated as like this:

  $anti{\ln }_{a}b=a^b$

Calculation:

Consider the given expression,

  $anti\ln \left(-3.7612\right)$

Rewrite the above expression as like this,

  $anti\ln \left(-3.7612\right)=anti{\log }_e\left(-3.7612\right)$

Now, apply the property of antilog functions:

  $\begin{array}{c}anti{\log }_e\left(-3.7612\right)=e^{-3.7612}\\ =0.0233\end{array}$

Therefore, the value of $anti\ln \left(-3.7612\right)$ is $0.0233$ .