Chapter 11, Problem 34SGA

To determine

Evaluate the expression.

Answer to Problem 34SGA

  $5$

Explanation of Solution

Given information:

  ${\log }_{2}32$

Calculation:

Consider the given expression,

  $x={\log }_{2}32$

  $\begin{array}{l}{2}^x=32\\ or\\ 2^x=2^5\left[equatepowers\right]\\ x=5\left[\therefore a^u=a^{v}thenu=v\right]\end{array}$

Hence, the evaluation of ${\log }_{2}32$ is $5$ .