Chapter 11.5, Problem 6MRE

To determine

To calculate:

Given equation.

  $\sqrt{x^2+y^2}$

Answer to Problem 6MRE

Value of $\sqrt{x^2+y^2}$ when $x=-2,y=8$ is $7.74$ .

Explanation of Solution

Give information:

  $x=-2,y=8$

Calculation:

Given equation is,

  $\sqrt{x^2+y^2}$

And $x=-2,y=8$

Substitute the $x=-2,y=8$ in the above equation,

  $\begin{array}{l}=\sqrt{x^2+y^2}\\ =\sqrt{{\left(-2\right)}^2+{\left(8\right)}^2}\end{array}$

Simplify,

  $\begin{array}{l}=\sqrt{-4+64}\\ =\sqrt{60}\\ =7.74\end{array}$

Therefore, value of $\sqrt{x^2+y^2}$ when $x=-2,y=8$ is $7.74$ .