Chapter 11.4, Problem 4OE

To determine

To explain:

First and last term of ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$

Answer to Problem 4OE

First term is $4$ and last term is $-3$ for ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$ .

Explanation of Solution

Give information:

Expression:

  ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$

The formula for finding series is,

  ${\displaystyle \sum _{i=1}^{n}C}$

Where,

  $i=$ index of summation.

  $C=$ Summand of the given expression.

  $n=$ upper limit of summation.

  $1=$ lower limit of summation.

After comparing to the summation formula,

In given expression ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$ ,

First term is $4$ while last term in explicit formula is $-3$ .

Therefore, First term is $4$ and last term is $-3$ .