Chapter 11.4, Problem 1OE

To determine

To explain:

Index of ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$

Answer to Problem 1OE

Index is $m=2$ .

Explanation of Solution

Give information:

Expression:

  ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$

The formula for finding series is,

  ${\displaystyle \sum _{i=1}^{n}C}$

Where,

  $i=$ index,

  $C=$ Number.

  $n=$ number of terms.

After comparing to the summation formula,

In given ${\displaystyle \sum _{m=2}^5\left(4m^2-3\right)}$ ,

Index is $m=2$ .

Therefore, index is $m=2$ .