Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)
6th Edition
ISBN: 9781524908102
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Chapter 11.5, Problem 60PS
To determine
To calculate: the values of
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Let F(u, v) = eu+v, u =
Use the Chain Rule to calculate the partial derivative.
(Use symbolic notation and fractions where needed. Express the answer in terms of independent variables.)
OF
ду
x²
xº, v = 7xy.
=
If the partial derivatives of A, B. U, and Vare assumed to exist, then
I.
V(U + V) = VU + VV or grad (U+ )3grad u+ grad V
2.
V (A +B) = V-A+V B or div (A + B) +div A + div B
3.
Vx (A +B) = VxA+VxB or curl (A + B) = curlA+ curl B
4.
V.(UA) = (VU) - A+ U(V A)
5.
Vx (UA) = (VU) xA + U(V x A)
6.
V.(A x B) = B (Vx A)-A (Vx B)
7. Vx (A x B) = (B V)A- B(V A)-(A V)B+ A(V B)
8.
V(A B) (B V)A+ (A V)B+ Bx (Vx A) + A x (V x B)
9. V.(VU) = VU=
is called the Laplacian of U.
+.
and V =.
ar dyaz
is called the Lapacian operator.
10. Vx (VU) =0. The curl of the gradient of U is zero,
11. V.(Vx A) = 0. The divergence of the curl of A is zero.
12. Vx (Vx A)= V(V. A)-V A
Find ∂x/∂u and ∂y/∂u if the equations u = x2 - y2 and y = x2 - y define x and y as functions of the independent variables u and y, and the partial derivatives exist. Then let s = x2 + y2 and find ∂s/∂u.
Chapter 11 Solutions
Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)
Ch. 11.1 - Prob. 1PSCh. 11.1 - Prob. 2PSCh. 11.1 - Prob. 3PSCh. 11.1 - Prob. 4PSCh. 11.1 - Prob. 5PSCh. 11.1 - Prob. 6PSCh. 11.1 - Prob. 7PSCh. 11.1 - Prob. 8PSCh. 11.1 - Prob. 9PSCh. 11.1 - Prob. 10PS
Ch. 11.1 - Prob. 11PSCh. 11.1 - Prob. 12PSCh. 11.1 - Prob. 13PSCh. 11.1 - Prob. 14PSCh. 11.1 - Prob. 15PSCh. 11.1 - Prob. 16PSCh. 11.1 - Prob. 17PSCh. 11.1 - Prob. 18PSCh. 11.1 - Prob. 19PSCh. 11.1 - Prob. 20PSCh. 11.1 - Prob. 21PSCh. 11.1 - Prob. 22PSCh. 11.1 - Prob. 23PSCh. 11.1 - Prob. 24PSCh. 11.1 - Prob. 25PSCh. 11.1 - Prob. 26PSCh. 11.1 - Prob. 27PSCh. 11.1 - Prob. 28PSCh. 11.1 - Prob. 29PSCh. 11.1 - Prob. 30PSCh. 11.1 - Prob. 31PSCh. 11.1 - Prob. 32PSCh. 11.1 - Prob. 33PSCh. 11.1 - Prob. 34PSCh. 11.1 - Prob. 35PSCh. 11.1 - Prob. 36PSCh. 11.1 - Prob. 37PSCh. 11.1 - Prob. 38PSCh. 11.1 - Prob. 39PSCh. 11.1 - Prob. 40PSCh. 11.1 - Prob. 41PSCh. 11.1 - Prob. 42PSCh. 11.1 - Prob. 43PSCh. 11.1 - Prob. 44PSCh. 11.1 - Prob. 45PSCh. 11.1 - Prob. 46PSCh. 11.1 - Prob. 47PSCh. 11.1 - Prob. 48PSCh. 11.1 - Prob. 49PSCh. 11.1 - Prob. 50PSCh. 11.1 - Prob. 51PSCh. 11.1 - Prob. 52PSCh. 11.1 - Prob. 53PSCh. 11.1 - Prob. 54PSCh. 11.1 - Prob. 55PSCh. 11.1 - Prob. 56PSCh. 11.1 - Prob. 57PSCh. 11.1 - Prob. 58PSCh. 11.1 - 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- Let , be the line passing through A=(3, 1, 2) and B = (-1,0, 1) and let , be the line passing though C= (1, 1, 1) and D= (-1, 2, 0). Use partial derivatives to the points on , and that are nearest to each other. Using these points, what is the distance between the lines, and £₂.arrow_forwardSuppose that the real variables p, v, t, and u satisfy the equations f(p, v, t, u) = 0, g(p, v,t, u) = 0, and that these two equations can be solved for any two of the four variables as functions of the other two. Then the symbol du/dp, for example, is ambiguous. We denote by (du/dp)t the partial derivative of u with respect to p, with u and v considered as functions of p and t, and by (8u/@p), the partial derivative of u with respect to p, with u and t considered as functions of p and v. With this notation, show that ).- G).C).- G),C). - O). ди dt dt dt dp dp All functions that appear in this problem may be assumed to be defined and differen- tiable in a suitable set to make the arguments work.arrow_forwardBoth first partial derivatives of the function f(x,y) are zero at the given points. Use the second-derivative test to determine the nature of f(x,y) at each of these points. If the second-derivative test is inconclusive, so state. f(x,y) = -9х + 18ху - у + 81y; (- 3, - 3), (9,9) What is the nature of the function at (- 3, - 3)? O A. f(x,y) has neither a relative maximum nor a relative minimum at (-3, - 3). B. f(x,y) has a relative maximum at (- 3, - 3). C. f(x,y) has a relative minimum at (- 3, - 3). D. The second-derivative test is inconclusive at (- 3, – 3). What is the nature of the function at (9,9)? O A. f(x,y) has neither a relative maximum nor a relative minimum at (9,9). B. f(x,y) has a relative minimum at (9,9). O C. f(x,y) has a relative maximum at (9,9). O D. The second-derivative test is inconclusive at (9,9).arrow_forward
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