
(a)
Interpretation:
The predominant molecular force present in
Concept Introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion (Induced dipole-induced dipole forces)
- Dipole-dipole
- Hydrogen bonding
(b)
Interpretation:
The predominant molecular force present in liquid
Concept Introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion
- Dipole-dipole
- Hydrogen bonding
(c)
Interpretation:
The predominant molecular force present in
Concept introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion
- Dipole-dipole
- Hydrogen bonding

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Chapter 11 Solutions
CHEMISTRY+CHEM...HYBRID ED.(LL)>CUSTOM<
- > H₂C=C-CH2-CH3 B. H₂O Pt C. + H2 + H₂O H D. 16. Give the IUPAC name for each of the following: B. Cl Cl c. Cl Cl 17. Draw the line-angle formula for each of the following compounds: 1. phenol 2. 1,3-dichlorobenzene 3. 4-ethyltoluene < Previous Submit Assignment Next ▸arrow_forwardno Ai walkthroughsarrow_forwardThe answer is shown. What is the reaction mechanism to arrive at the answer?arrow_forward
- no Ai walkthroughsarrow_forwardConsider the following nucleophilic substitution reaction. The compound listed above the arrow is the solvent for the reaction. If nothing is listed over the arrow, then the nucleophile is also the solvent for the reaction. Part 1 of 2 Br CH,CN + I¯ What is the correct mechanism for the reaction? Select the single best answer. @SN2 ○ SN 1 Part: 1/2 Part 2 of 2 Draw the products for the reaction. Include both the major organic product and the inorganic product. If more than one stereoisomer is possible, draw only one stereoisomer. Include stereochemistry where relevant. Click and drag to start drawing a structure. X હૈarrow_forward20.33 Think-Pair-Share (a) Rank the following dienes and dienophiles in order of increasing reactivity in the Diels-Alder reaction. (i) CO₂Et (ii) COEt || CO₂Et MeO MeO (b) Draw the product that results from the most reactive diene and most reactive dienophile shown in part (a). (c) Draw a depiction of the orbital overlap involved in the pericyclic reaction that oc- curs between the diene and dienophile in part (b). (d) Is the major product formed in part (b) the endo or exo configuration? Explain your reasoning.arrow_forward
- 20.40 The following compound undergoes an intramolecular Diels-Alder reaction to give a tricyclic product. Propose a structural formula for the product. CN heat An intramolecular Diels-Alder adductarrow_forwardWhat is the reaction mechanism for this? Can this even be done without a base?arrow_forwardWhat is the reaction mechanism for this?arrow_forward
- What is the reaction mechanism for this?arrow_forwardWhat is the reaction mechanism for this?arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. + Drawing Arrows CH3ONA, CH3OH heat : Br:O Na → H H Br Na + H H H H H :0: .H + Undo Reset Done Q CH3 Drag To Pan +arrow_forward
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