Chapter 11.4, Problem 32ES

It is a theorem of solid geometry that the volume of a tetrahedron is $\frac{1}{3}\left(\text{area of base}\right)\cdot \left(\text{height}\right)\text{.}$ Use this result to prove that the volume of a tetrahedron with adjacent edges given by the vectors u, v, and w is $\frac{1}{6}\left|\text{u}\cdot \left(\text{v}\times \text{w}\right)\right|.$