Explanation Initial velocity of the hockey puck is equal to v 0 = 90 m i / h For a uniformly accelerated motion, x = x 0 + v 0 t + 1 2 a t 2 In above equation, x - End distance x 0 - Start distance v 0 - Initial velocity t - Elapsed time a -Acceleration Calculation: Convert v 0 = 90 m i / h = 132 f t / s Therefore, v x 0 = 132 cos α v y 0 = 132 sin α For horizontal motion, x = x 0 + v x 0 t + 1 2 a t 2 16 f t = 0 + 132 cos α t + 0 Therefore, t = 4 33 cos α For vertical motion, y = y 0 + v y 0 t + 1 2 a t 2 y = 132 sin α t + 1 2 ( − g ) t 2 Substitute for t y = 132 sin α ( 4 33 cos α ) − To determine (b) The corresponding time

12th Edition

ISBN: 9781259977305

Author: BEER, Ferdinand P. (ferdinand Pierre), Johnston, E. Russell (elwood Russell), Cornwell, Phillip J., SELF, Brian P.

Publisher: Mcgraw-hill Education,

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Question

Chapter 11.4, Problem 11.113P

To determine

(a)

The largest value of angle α which the puck will enter the net

To determine

(b)

The corresponding time

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Chapter 11.4, Problem 11.112P

Chapter 11.4, Problem 11.114P

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(a) The largest value of angle α which the puck will enter the net

Solution Summary: The author explains that the initial velocity of the hockey puck is equal to v_0=90mi/h for a uniformly accelerated motion.