Chapter 11.3, Problem 86S

To determine

Find the value of $\frac{3ab}{c}\text{when}a=-2;b=\frac{1}{3};\text{and}c=-12$

Answer to Problem 86S

  $\frac{3ab}{c}=\frac{1}{6}$

Explanation of Solution

Given:

Find the value of $\frac{3ab}{c}\text{when}a=-2;b=\frac{1}{3};\text{and}c=-12$

Concept Used:

Substitute the values of a, b and c in the expression $\frac{3ab}{c}$

Calculation:

  $\text{Find}:\frac{3ab}{c}\text{when}a=-2;b=\frac{1}{3};\text{and}c=-12$

  $\frac{3ab}{c}=\frac{3·(-2)·\frac{1}{3}}{-12}=\frac{-2}{-12}=\frac{1}{6}$

Thus, $\frac{3ab}{c}=\frac{1}{6}$