Chapter 11.2, Problem 15PPS

To determine

Find the 66^th term of the arithmetic sequence with $a_1=-12;d=4;n=66$

Answer to Problem 15PPS

  $a_{66}=242$

Explanation of Solution

Given:

  $a_1=-12;d=4;n=66$

Concept Used:

The nth term formula for Arithmetic Sequence: $a_n=a_1+(n-1)·d$

Given: $a_1=-12;d=4;n=66$

Calculation:

Given: $a_1=-12;d=4;n=66$

  $\begin{array}{l}{a}_1=-12;d=4;n=66\\ a_n=a_1+(n-1)·4\\ a_{66}=-12+(66-1)·4=-12+65·4=-12+260=242\\ a_{66}=242\end{array}$

Thus, $a_{66}=242$