Chapter 11.2, Problem 14PPS

To determine

Find the 16^th term of the arithmetic sequence with $a_1=-18;d=12;n=16$

Answer to Problem 14PPS

  $a_{16}=162$

Explanation of Solution

Given:

Find the 16^th term of the arithmetic sequence with $a_1=-18;d=12;n=16$

Concept Used:

The nth term formula for Arithmetic Sequence: $a_n=a_1+(n-1)·d$

Given: $a_1=-18;d=12;n=16$

Calculation:

Given: $a_1=-18;d=12;n=16$

  $\begin{array}{l}{a}_1=-18;d=12;n=16\\ a_n=a_1+(n-1)·d\\ a_{16}=-18+(16-1)·12=-18+15·12=-18+180=162\\ a_{16}=162\end{array}$

Thus, $a_{16}=162$