The nuclear equation that is not balanced has to be chosen from the given options. Concept Introduction: If the reaction occurs in the nucleus of an atom then it is known as nuclear reaction. These reactions are not considered as ordinary chemical reactions because the electrons do not take part in reaction while the particle inside the nucleus does. Isotope and nuclide are almost similar terms. Isotopes refer to the same element that has different mass number while nuclide refers to atoms of same or different elements with specific atomic number and mass number. This nuclear reaction can be represented by nuclear equation. This is not a normal chemical equation. Nuclear equation considers the mass number and atomic number of the reactants and products. Unstable nucleus tends to emit radiation spontaneously. During this process the nuclide is transformed into nuclide of another element. Parent nuclide is the one which undergoes the radioactive decay. Daughter nuclide is the one that is formed from parent nuclide after radioactive decay. The radioactive decay can take place by emission of alpha particle, beta particle or gamma ray emission. Alpha particle decay is a process in which an alpha particle is emitted. This results in the formation of nuclide of different element that has atomic number that is 2 less and mass number that is 4 less than the original nucleus. Beta particle decay is a process in which a beta particle is emitted. This produces a nuclide of different element similar to that of alpha particle decay. The mass number is same as that of parent nuclide while the atomic number increases by 1 unit. Gamma ray emission is a process in which the unstable nucleus emits gamma ray. This occurs along with alpha or beta particle emission. The gamma rays are not shown in the nuclear equation because they do not affect balancing the nuclear equation.

Question

Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$

Answer 1

Question

Chapter 11.3, Problem 1QQ

Interpretation Introduction

Interpretation:

The nuclear equation that is not balanced has to be chosen from the given options.

Concept Introduction:

If the reaction occurs in the nucleus of an atom then it is known as nuclear reaction. These reactions are not considered as ordinary chemical reactions because the electrons do not take part in reaction while the particle inside the nucleus does. Isotope and nuclide are almost similar terms. Isotopes refer to the same element that has different mass number while nuclide refers to atoms of same or different elements with specific atomic number and mass number.

This nuclear reaction can be represented by nuclear equation. This is not a normal chemical equation. Nuclear equation considers the mass number and atomic number of the reactants and products. Unstable nucleus tends to emit radiation spontaneously. During this process the nuclide is transformed into nuclide of another element. Parent nuclide is the one which undergoes the radioactive decay. Daughter nuclide is the one that is formed from parent nuclide after radioactive decay.

The radioactive decay can take place by emission of alpha particle, beta particle or gamma ray emission. Alpha particle decay is a process in which an alpha particle is emitted. This results in the formation of nuclide of different element that has atomic number that is 2 less and mass number that is 4 less than the original nucleus. Beta particle decay is a process in which a beta particle is emitted. This produces a nuclide of different element similar to that of alpha particle decay. The mass number is same as that of parent nuclide while the atomic number increases by 1 unit. Gamma ray emission is a process in which the unstable nucleus emits gamma ray. This occurs along with alpha or beta particle emission. The gamma rays are not shown in the nuclear equation because they do not affect balancing the nuclear equation.

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Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$

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