The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p = 60 q 0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200 ≤ q ≤ 800 .

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Answer 1

Question

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

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Answer 2

Question

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

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Answer 3

Question

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

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Answer 4

Question

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

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Answer 5

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 6

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 7

Chapter 11.2, Problem 20E

(a)

To determine

To calculate: The price that the town’s fishery should charge in order to produce a demand of 400 pounds of tuna per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 8

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 9

(b)

To determine

To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 10

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

Answer 11

(c)

To determine

To calculate: The revenue and marginal revenue at a demand level of 400 pounds per month such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800 and also interpret the answers.

Answer 12

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 13

(d)

To determine

The recommendation that whether the fishery should raise or lower the prices of tuna to increase its revenue if town fishery’s catch monthly tuna amounted to 400 pounds and the price is same as in part (a) such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Solution Summary: The author calculates the price that the town's fishery should charge to produce a demand for 400 pounds of tuna per month.

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To calculate: The monthly revenue R as the function of q such that demand equation for tuna is given by the function p=60q0.5 where p is the price in dollars and q is the number of pounds of tuna that can be sold for a price p and lies in the range 200≤q≤800.

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