To determine The maximum spacing ( s ) of nails for region AB . The maximum spacing ( s ′ ) of nails for region BC . The maximum spacing ( s ″ ) of nails for region CD . Explanation Given information: Each nail can support a shear force of 50 lb. Calculation: Sketch the free body diagram of beam as shown in Figure 1. Let B y is the reaction at B and D y is the reaction at point D . Calculate the reaction for support. Taking a moment about D . ∑ M D = 0 ( 800 × 15 ) + ( 1 , 200 × 5 ) = B y × 10 12 , 000 + 6 , 000 = 10 B y 18 , 000 = 10 B y B y = 1 , 800 lb Summation of force in vertical direction: ∑ F y = 0 B y + D y = Total load (1) Substitute 1 , 800 lb for B y and 2 , 000 lb for total load in Equation (1). 1 , 800 + D y = 2 , 000 D y = 2 , 000 − 1 , 800 D y = 200 lb Sketch the calculated values as shown in Figure 2. Calculate the shear force as follows: Calculate the shear force 0 ft from point A : S F @ A = − 800 lb Calculate the shear force 5 ft from point A : S F @ 5 ft = 1 , 800 − 800 = 1 , 000 lb Calculate the shear force at 10 ft from point A : S F @ 10 ft = 1 , 800 − 800 − 1 , 200 = 1 , 000 − 1 , 200 = − 200 lb Calculate the shear force 15 ft from point A : S F @ 15 ft = 1 , 800 − 800 − 1 , 200 + 200 = 1 , 000 − 100 = 0 Sketch the shear force diagram as shown in Figure 3 Sketch the cross section of boards as shown in Figure 4 Refer to Figure 4: The width and depth of the rectangle 1 is b 1 = 8 in . and d 1 = 1 in . The width and depth of the rectangle 2 is b 2 = 1 in . and d 2 = 6 in . Calculate the area of section 1 as follows: a 1 = b 1 d 1 (2) Substitute 8 in. for b 1 and 1 in. for d 1 in Equation (2). a 1 = 8 × 1 = 8 in 2 Calculate the area of section 2 as follows: a 2 = b 2 d 2 (3) Substitute 1 in. for b 2 and 6 in. for d 2 in Equation (3). a 2 = 1 × 6 = 6 in 2 Calculate the centroid y ¯ as follows: Find the centroid y 1 . y 1 = d 1 2 (4) Substitute 1 in. for d 1 in Equation (4). y 1 = 1 2 = 0.5 in . Find the centroid y 2 . y 2 = d 2 2 + d 1 (5) Substitute 1 in. for d 1 and 6 in. for d 2 in Equation (5). y 2 = 6 2 + 1 = 3 + 1 = 4 in . Calculate the centroid y ¯ as follows: y ¯ = a 1 y 1 + a 2 y 2 a 1 + a 2 (6) Here, a 1 is the area of section 1, a 2 is area of section 2, y 1 is centroid of section rectangle 1, and y 2 is centroid of section rectangle 2. Substitute 8 in 2 for a 1 , 6 in 2 for a 2 , 0.5 in . for y 1 , and 4 in. mm for y 2 in Equation (6). y ¯ = ( 8 × 0.5 ) + 2 ( 6 × 4 ) 8 + 2 ( 6 ) = 4 + 48 20 = 52 20 = 2.6 in . Calculate the moment of inertia ( I ) of beam as follows: I = [ ( b 1 d 1 3 12 + b 1 d 1 ( y ¯ − y 1 ) 2 ) + 2 ( b 2 d 2 3 12 + b 2 d 2 ( y 2 − y ¯ ) 2 ) ] (7) Substitute 8 in

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ISBN: 9780133254426

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Chapter 11.2, Problem 11.23P

To determine

The maximum spacing (s) of nails for region AB.

The maximum spacing (s′) of nails for region BC.

The maximum spacing (s″) of nails for region CD.

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Chapter 11.2, Problem 11.22P

Chapter 11.2, Problem 11.24P

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Mechanics of Materials

Ch. 11.2 - Determine the minimum dimension a to the nearest...Ch. 11.2 - of the rod to safely support the load. The rod is...Ch. 11.2 - The wood has an allowable normal stress of allow =...Ch. 11.2 - of the beam's cross section to safely support the...Ch. 11.2 - Determine the minimum dimension b to the nearest...Ch. 11.2 - The beam is made of steel having an allowable...Ch. 11.2 - Determine its dimensions if it is to be...Ch. 11.2 - Determine the minimum width of the beam to the...Ch. 11.2 - if P=10 kip.Ch. 11.2 - If the allowable bending stress is allow = 22 ksi...

Ch. 11.2 - The allowable bending stress is allow = 24 ksi and...Ch. 11.2 - The allowable bending stress is allow = 22 ksi and...Ch. 11.2 - 11–7. Draw the shear and moment diagrams for the...Ch. 11.2 - *11–8. The simply supported beam is made of timber...Ch. 11.2 - The beam has an allowable normal stress of allow =...Ch. 11.2 - The beam has an allowable normal stress of allow...Ch. 11.2 - 11–11. The timber beam is to be loaded as shown....Ch. 11.2 - If each beam is to be designed to carry 90 lb/ft...Ch. 11.2 - 11–13. Select the lightest steel wide-flange beam...Ch. 11.2 - 11–14. Select the lightest-weight steel...Ch. 11.2 - Prob. 11.15P Ch. 11.2 - The beam has an allowable normal stress of allow....Ch. 11.2 - Determine the maximum cable force P that can...Ch. 11.2 - to safely support the load. The wood has an...Ch. 11.2 - and the wood has an allowable normal stress of...Ch. 11.2 - Prob. 11.20P Ch. 11.2 - Prob. 11.21P Ch. 11.2 - Prob. 11.22P Ch. 11.2 - 11–23. The beam is constructed from three boards...Ch. 11.2 - Prob. 11.24P Ch. 11.2 - Prob. 11.25P Ch. 11.2 - Select the lightest-weight wide-flange beam from...Ch. 11.2 - Prob. 11.27P Ch. 11.2 - * 11–28. The joist AB used in housing construction...Ch. 11.2 - If the maximum bending stress is not to exceed...Ch. 11.2 - 11–30. The simply supported beam supports a load...Ch. 11.4 - Determine the variation in the width was a...Ch. 11.4 - Prob. 11.32P Ch. 11.4 - Prob. 11.33P Ch. 11.4 - The beam is made from a plate that has a constant...Ch. 11.4 - Determine the variation in the depth d of a...Ch. 11.4 - Determine the variation of the radius r of the...Ch. 11.4 - Prob. 11.37P Ch. 11.4 - Determine the variation in the width b as a...Ch. 11.4 - The tubular shaft has an inner diameter of 15 mm....Ch. 11.4 - Prob. 11.40P Ch. 11.4 - Prob. 11.41P Ch. 11.4 - Prob. 11.42P Ch. 11.4 - Prob. 11.43P Ch. 11.4 - Prob. 11.44P Ch. 11.4 - Prob. 11.45P Ch. 11.4 - Prob. 11.46P Ch. 11 - The cantilevered beam has a circular cross...Ch. 11 - Select the lightest-weight wide-flange overhanging...Ch. 11 - Prob. 11.49RP Ch. 11 - Determine the shaft's diameter to the nearest...Ch. 11 - Select the lightest-weight wide-flange beam from...Ch. 11 - The simply supported joist is used in the...Ch. 11 - The simply supported joist is used in the...Ch. 11 - by 4-in. pieces of wood braced as shown. If the...

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