Concept explainers
a)
To find the degrees of freedom.
a)

Answer to Problem 6E
The df = 2
Explanation of Solution
Given:
Color | Observed Count | Frequency | Expected count |
Red | 85 | 0.47 | 94.74 |
Black | 99 | 0.47 | 94.74 |
Green | 16 | 0.05 | 10.53 |
Total | 200 | 1.00 | 200 |
The chi-square test statistic = 4.04
Calculation:
The expected counts are large enough to use a chi-square distribution if all expected counts are at least 5. This condition is satisfied.
The degrees of freedom = df = c-1 = 3-1 = 2
b)
To find the p-value using table and technology.
b)

Answer to Problem 6E
The p-value = 0.1108
Explanation of Solution
Given:
Color | Observed Count | Frequency | Expected count |
Red | 85 | 0.47 | 94.74 |
Black | 99 | 0.47 | 94.74 |
Green | 16 | 0.05 | 10.53 |
Total | 200 | 1.00 | 200 |
The chi-square test statistic = 4.04
The degrees of freedom = 2
Calculation:
The p-value using table for df = 2 is,
0.10 < P < 0.15
The excel formula, =CHIDIST(4.40,2)
P-value = 0.1108
c)
To explain the conclusion.
c)

Answer to Problem 6E
There is not sufficient evidence to reject the claim about the specified probability distribution.
Explanation of Solution
Given:
Color | Observed Count | Frequency | Expected count |
Red | 85 | 0.47 | 94.74 |
Black | 99 | 0.47 | 94.74 |
Green | 16 | 0.05 | 10.53 |
Total | 200 | 1.00 | 200 |
The chi-square test statistic = 4.04
The degrees of freedom = 2
The p-value = 0.1108
Calculation:
Here, p-value > 0.05, fail to reject H0.
There is not sufficient evidence to reject the claim about the specified probability distribution.
Chapter 11 Solutions
PRACTICE OF STATISTICS F/AP EXAM
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