PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 11.1, Problem 6E

a)

To determine

To find the degrees of freedom.

a)

Expert Solution
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Answer to Problem 6E

The df = 2

Explanation of Solution

Given:

    Color Observed Count Frequency Expected count
    Red 85 0.47 94.74
    Black 99 0.47 94.74
    Green 16 0.05 10.53
    Total 200 1.00 200

The chi-square test statistic = 4.04

Calculation:

The expected counts are large enough to use a chi-square distribution if all expected counts are at least 5. This condition is satisfied.

The degrees of freedom = df = c-1 = 3-1 = 2

b)

To determine

To find the p-value using table and technology.

b)

Expert Solution
Check Mark

Answer to Problem 6E

The p-value = 0.1108

Explanation of Solution

Given:

    Color Observed Count Frequency Expected count
    Red 85 0.47 94.74
    Black 99 0.47 94.74
    Green 16 0.05 10.53
    Total 200 1.00 200

The chi-square test statistic = 4.04

The degrees of freedom = 2

Calculation:

The p-value using table for df = 2 is,

0.10 < P < 0.15

The excel formula, =CHIDIST(4.40,2)

P-value = 0.1108

c)

To determine

To explain the conclusion.

c)

Expert Solution
Check Mark

Answer to Problem 6E

There is not sufficient evidence to reject the claim about the specified probability distribution.

Explanation of Solution

Given:

    Color Observed Count Frequency Expected count
    Red 85 0.47 94.74
    Black 99 0.47 94.74
    Green 16 0.05 10.53
    Total 200 1.00 200

The chi-square test statistic = 4.04

The degrees of freedom = 2

The p-value = 0.1108

Calculation:

Here, p-value > 0.05, fail to reject H0.

There is not sufficient evidence to reject the claim about the specified probability distribution.

Chapter 11 Solutions

PRACTICE OF STATISTICS F/AP EXAM

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