FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
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Chapter 11, Problem 92CE
Interpretation Introduction
Interpretation:
The complete Lewis structures of the given compound have to be drawn. The different molecular geometries around each atom have to be identified. The atoms possessing tetrahedral geometry has to be rounded by circles, trigonal planar geometry has to be indicated by squares, trigonal pyramid geometry has to be denoted by pentagon, bent geometry has to be indicated by hexagon and atoms having unexpected number of bonds has to be indicated by triangle.
Concept Introduction:
Lewis structure:
The representation of valence shell electrons around the atom is known as Lewis structure or Lewis dot structure. Electrons are represented as a dot in Lewis structures, a single dot represents unpaired electron and paired of dots represents paired electrons.
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In the first column type the number of atoms in the covalent compound. In the second
column, type the total number of VALENCE electrons in the compound (all electrons:
shared and unshared electrons). In the third column, determine the total number of
possible chemical bonds in the compound.
Compound
H₂
Cl₂
0₂
N₂
H₂O
SF₂
CH4
NH3
PF3
CC14
CHEMISTRY
Covalent Compounds and Electrons
C₂H6
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Total Valence
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BHE
Total possible of
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TT
In the first column type the number of atoms in the covalent compound. In the second
column, type the total number of VALENCE electrons in the compound (all electrons:
shared and unshared electrons). In the third column, determine the total number of
possible chemical bonds in the compound.
Compound
H₂
Cl₂
0₂
N₂
H₂O
SF2
CH4
NH3
PF3
CC14
C₂H6
CHEMISTRY
Covalent Compounds and Electrons
Number of
Atoms
I
Total Valence
Electrons
Total possible of
chemical bonds
Using the answers to the questions attached answer the question: Why are compounds composed of integer ratios of elements?
Chapter 11 Solutions
FOUND.OF COLLEGE CHEMISTRY
Ch. 11.1 - Prob. 11.1PCh. 11.2 - Prob. 11.2PCh. 11.3 - Prob. 11.3PCh. 11.4 - Prob. 11.4PCh. 11.4 - Prob. 11.5PCh. 11.5 - Prob. 11.6PCh. 11.6 - Prob. 11.7PCh. 11.6 - Prob. 11.8PCh. 11.7 - Prob. 11.9PCh. 11.8 - Prob. 11.10P
Ch. 11.9 - Prob. 11.11PCh. 11.10 - Prob. 11.12PCh. 11 - Prob. 1RQCh. 11 - Prob. 2RQCh. 11 - Prob. 3RQCh. 11 - Prob. 4RQCh. 11 - Prob. 5RQCh. 11 - Prob. 6RQCh. 11 - Prob. 7RQCh. 11 - Prob. 8RQCh. 11 - Prob. 9RQCh. 11 - Prob. 10RQCh. 11 - Prob. 11RQCh. 11 - Prob. 12RQCh. 11 - Prob. 13RQCh. 11 - Prob. 14RQCh. 11 - Prob. 15RQCh. 11 - Prob. 16RQCh. 11 - Prob. 17RQCh. 11 - Prob. 18RQCh. 11 - Prob. 19RQCh. 11 - Prob. 20RQCh. 11 - Prob. 21RQCh. 11 - Prob. 22RQCh. 11 - Prob. 23RQCh. 11 - Prob. 24RQCh. 11 - Prob. 25RQCh. 11 - Prob. 26RQCh. 11 - Prob. 28RQCh. 11 - Prob. 30RQCh. 11 - Prob. 31RQCh. 11 - Prob. 33RQCh. 11 - Prob. 36RQCh. 11 - Prob. 1PECh. 11 - Prob. 2PECh. 11 - Prob. 3PECh. 11 - Prob. 4PECh. 11 - Prob. 5PECh. 11 - Prob. 6PECh. 11 - Prob. 7PECh. 11 - Prob. 8PECh. 11 - Prob. 9PECh. 11 - Prob. 10PECh. 11 - Prob. 11PECh. 11 - Prob. 12PECh. 11 - Prob. 13PECh. 11 - Prob. 14PECh. 11 - Prob. 15PECh. 11 - Prob. 16PECh. 11 - Prob. 17PECh. 11 - Prob. 18PECh. 11 - Prob. 19PECh. 11 - Prob. 20PECh. 11 - Prob. 21PECh. 11 - Prob. 22PECh. 11 - Prob. 23PECh. 11 - Prob. 24PECh. 11 - Prob. 25PECh. 11 - Prob. 26PECh. 11 - Prob. 27PECh. 11 - Prob. 28PECh. 11 - Prob. 29PECh. 11 - Prob. 30PECh. 11 - Prob. 31PECh. 11 - Prob. 32PECh. 11 - Prob. 33PECh. 11 - Prob. 34PECh. 11 - Prob. 35PECh. 11 - Prob. 36PECh. 11 - Prob. 37PECh. 11 - Prob. 38PECh. 11 - Prob. 39PECh. 11 - Prob. 40PECh. 11 - Prob. 47PECh. 11 - Prob. 48PECh. 11 - Prob. 49PECh. 11 - Prob. 50PECh. 11 - Prob. 51PECh. 11 - Prob. 52PECh. 11 - Prob. 55AECh. 11 - Prob. 56AECh. 11 - Prob. 57AECh. 11 - Prob. 58AECh. 11 - Prob. 59AECh. 11 - Prob. 63AECh. 11 - Prob. 64AECh. 11 - Prob. 65AECh. 11 - Prob. 66AECh. 11 - Prob. 67AECh. 11 - Prob. 68AECh. 11 - Prob. 76AECh. 11 - Prob. 77AECh. 11 - Prob. 78AECh. 11 - Prob. 81AECh. 11 - Prob. 82AECh. 11 - Prob. 83AECh. 11 - Prob. 84AECh. 11 - Prob. 85AECh. 11 - Prob. 86AECh. 11 - Prob. 87AECh. 11 - Prob. 88CECh. 11 - Prob. 89CECh. 11 - Prob. 90CECh. 11 - Prob. 92CECh. 11 - Prob. 93CECh. 11 - Prob. 94CECh. 11 - Prob. 95CE
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- Draw Lewis structures to illustrate the bonding in the following molecules. In each case, there will be at least one multiple bond present in a molecule. a. COCl2: Both chlorine atoms and the oxygen atom are bonded to the carbon atom. b. C2H2Br2: The two carbon atoms are bonded to one another. Each carbon atom also has a bromine atom and a hydrogen atom bonded to it. c. C2N2: The two carbon atoms are bonded to one another, and each carbon atom also has a nitrogen bonded to it. d. CH2N2: A central carbon atom has both nitrogen atoms bonded to it. Both hydrogen atoms are bonded to one of the two nitrogen atoms.arrow_forwardDraw Lewis structures showing all valence electrons for these molecules. (a) C2H6 (b) CS2 (c) HCNarrow_forwardDraw Lewis structures to illustrate the covalent bonding in the following diatomic molecules. a. Cl2 b. HCl c. BrCl d. ClFarrow_forward
- Without actually drawing the Lewis structure, determine how many valence electrons are available for covalent bonding in each of the following molecules. a. CBr4 b. SF2 c. PH3 d. OF2arrow_forwardDraw Lewis structures to illustrate the covalent bonding in the following diatomic molecules. a. Br2 b. HBr c. BrF d. IBrarrow_forwarda. How many sticks did you need to make the skeleton structure?____________ b. How many sticks are left over? ____________ If your model is to obey the octet rule, each ball must have four sticks in it except for hydrogen atom balls, which need and can only have one. Each atom in an octet rule species is surrounded by four pairs of electrons. c. How many holes remain to be filled? ____________ Fill them with the remaining sticks, which represent nonbonding electron pairs. Draw the complete Lewis structure for NH2Cl using lines for bonds and pairs of dots for nonbonding electrons.arrow_forward
- Covalent bonding involves the sharing of electrons between atoms. The number of covalent bonds an atom can form relates to the number of electrons it can share and still result in a neutral molecule. It is important to know how many bonds certain elements are most likely to form in order to draw structural formulas for molecules.arrow_forwardI don't get it with this question. Can you help me, pleasearrow_forwardDecide whether these proposed Lewis structures are reasonable. proposed Lewis structure Is the proposed Lewis structure reasonable? Yes. No, it has the wrong number of valence electrons. The correct number is: Н — Н — О No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* Yes. No, it has the wrong number of valence electrons. The correct number is: 0=0= O No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* Yes. No, it has the wrong number of valence electrons. The correct number is: Н — СС — Н No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* * If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "O,0". :0: :0: :0 :arrow_forward
- Now, we will investigate diatomic molecules, those that are made up of two of the same type of atom. Select 2 fluorine atoms. How many valence electrons are in each fluorine atom? Is a fluorine atom a metal or a non-metal? Did the combination of these atoms create a covalent or ionic bond? How are the valence electrons organized to form a bond between these atoms? How is this different from the ionic bonds formed in the previous part of the activity?arrow_forwardRecognising exceptions to the octet rule.arrow_forwardPredicting the compound formed by two main group elements.arrow_forward
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