
Concept explainers
Interpretation:
For alkali metals in the periodic table, whether the first ionization energy will decrease or increase from top to bottom in a group has to be explained.
Concept Introduction:
Atomic radii:
The atomic radius of an atom can be defined as the distance between the center of the nucleus and the outermost electron. In the periodic table, across a period atomic radius is decreases and increases down a group.
Ionization energy:
The amount of energy required to remove an electron from the atom is known ionization energy. If the removed electron is first then it will be first ionization energy, if the removed electron is second then it will be second ionization energy.
For example,

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Chapter 11 Solutions
FOUND.OF COLLEGE CHEMISTRY
- Complete the following esterification reaction by drawing the structural formula of the product formed. HOH HO i catalyst catalyst OH HO (product has rum flavor) (product has orange flavor)arrow_forwardThe statements in the tables below are about two different chemical equilibria. The symbols have their usual meaning, for example AG stands for the standard Gibbs free energy of reaction and K stands for the equilibrium constant. In each table, there may be one statement that is faise because it contradicts the other three statements. If you find a false statement, check the box next to t Otherwise, check the "no false statements" box under the table. statement false? AG"1 no false statements: statement false? AG-0 0 InK-0 0 K-1 0 AH-TAS no false statements 2arrow_forwardComplete the following esterification reactions by drawing the line formulas of the carboxylic acid and alcohol required to form the ester shown. catalyst catalyst catalyst apricot fragrancearrow_forward
- Show the saponification products of the following ester: You don't need to draw in the Na+ cation. catalyst, A catalyst, A catalyst, Aarrow_forwardWhat would happen if the carboxylic acid and alcohol groups were on the same molecule? In essence, the molecule reacts with itself. Draw the structure of the products formed in this manner using the reactants below. If two functional groups interact with one another on the same molecule, this is called an “intramolecular" (within one) rather than "intermolecular" (between two or more) attack. OH OH catalyst OH HO catalyst catalyst HO OHarrow_forwardQ3: Write in the starting alkyl bromide used to form the following products. Include any reactants, reagents, and solvents over the reaction arrow. If more than one step is required, denote separate steps by using 1), 2), 3), etc. H OH racemic OH OH 5 racemicarrow_forward
- Draw the Lewis structure of the SO3-O(CH3)2 complex shown in the bottom right of slide 2in lecture 3-3 (“Me” means a CH3 group) – include all valence electron pairs and formal charges.From this structure, should the complex be a stable molecule? Explain.arrow_forwardPredict all organic product(s), including stereoisomers when applicable.arrow_forwardQ5: Propose a reasonable synthesis for the following decalin derivative. using only decalin and alkanes of 3 or fewer carbons. Decalin H3C HO க CH3arrow_forward
- 2Helparrow_forwardplease add appropriate arrows, and tell me clearly where to add arrows, or draw itarrow_forwardWhat I Have Learned Directions: Given the following reaction and the stress applied in each reaction, answer the question below. A. H2(g) + Cl2(g) 2 HCl(g) Stress applied: Decreasing the pressure 1. What is the Keq expression? 2. What will be the effect in the number of moles of HCl(g)? 3. What will be the Equilibrium Shift or the reaction? B. Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g) Stress applied: Increasing the temperature 1. What is the Keq expression?. 2. What will be the effect in the volume of water vapor collected? 3. What will be the Equilibrium Shift or the reaction? C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat Stress applied: Increasing the volume of the container 1. What is the Keq expression?. 2. What will be the effect in the amount of H₂O? 3. What will be the Equilibrium Shift or the reaction?arrow_forward
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