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FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
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Chapter 11, Problem 24RQ
Interpretation Introduction
Interpretation:
The number of shared electrons required to make a single covalent bond has to be given and also the maximum number of covalent bond formed between any two atoms has to be given.
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Students have asked these similar questions
how many shared electrons make up a single covelant bond? what is the maximum number of covalent bonds that can be formed between any two atoms
In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent
ions), which affects lattice energy (a measure of the attractive force holding those ions together).
Based on ion sizes, arrange these compounds by their expected lattice energy.
Note that many sources define lattice energies as negative values. Please arrange by magnitude and ignore the sign.
|lattice energy|
absolute value of the lattice energy
Greatest |lattice energy|
(strongest bonds)
Least |lattice energy|
(weakest bonds)
Answer Bank
CsF
CsI
CsBr
CSCI
In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions),
which affects lattice energy (a measure of the attractive force holding those ions together).
Based on ion sizes, arrange these compounds by their expected lattice energy.
Note that many sources define lattice energies as negative values. Please arrange by magnitude and ignore the sign.
|lattice energy|
absolute value of the lattice energy
Greatest |lattice energy|
(strongest bonds)
Least |lattice energy|
(weakest bonds)
Answer Bank
CsF
RbF
NaF
LiF
KF
Chapter 11 Solutions
FOUND.OF COLLEGE CHEMISTRY
Ch. 11.1 - Prob. 11.1PCh. 11.2 - Prob. 11.2PCh. 11.3 - Prob. 11.3PCh. 11.4 - Prob. 11.4PCh. 11.4 - Prob. 11.5PCh. 11.5 - Prob. 11.6PCh. 11.6 - Prob. 11.7PCh. 11.6 - Prob. 11.8PCh. 11.7 - Prob. 11.9PCh. 11.8 - Prob. 11.10P
Ch. 11.9 - Prob. 11.11PCh. 11.10 - Prob. 11.12PCh. 11 - Prob. 1RQCh. 11 - Prob. 2RQCh. 11 - Prob. 3RQCh. 11 - Prob. 4RQCh. 11 - Prob. 5RQCh. 11 - Prob. 6RQCh. 11 - Prob. 7RQCh. 11 - Prob. 8RQCh. 11 - Prob. 9RQCh. 11 - Prob. 10RQCh. 11 - Prob. 11RQCh. 11 - Prob. 12RQCh. 11 - Prob. 13RQCh. 11 - Prob. 14RQCh. 11 - Prob. 15RQCh. 11 - Prob. 16RQCh. 11 - Prob. 17RQCh. 11 - Prob. 18RQCh. 11 - Prob. 19RQCh. 11 - Prob. 20RQCh. 11 - Prob. 21RQCh. 11 - Prob. 22RQCh. 11 - Prob. 23RQCh. 11 - Prob. 24RQCh. 11 - Prob. 25RQCh. 11 - Prob. 26RQCh. 11 - Prob. 28RQCh. 11 - Prob. 30RQCh. 11 - Prob. 31RQCh. 11 - Prob. 33RQCh. 11 - Prob. 36RQCh. 11 - Prob. 1PECh. 11 - Prob. 2PECh. 11 - Prob. 3PECh. 11 - Prob. 4PECh. 11 - Prob. 5PECh. 11 - Prob. 6PECh. 11 - Prob. 7PECh. 11 - Prob. 8PECh. 11 - Prob. 9PECh. 11 - Prob. 10PECh. 11 - Prob. 11PECh. 11 - Prob. 12PECh. 11 - Prob. 13PECh. 11 - Prob. 14PECh. 11 - Prob. 15PECh. 11 - Prob. 16PECh. 11 - Prob. 17PECh. 11 - Prob. 18PECh. 11 - Prob. 19PECh. 11 - Prob. 20PECh. 11 - Prob. 21PECh. 11 - Prob. 22PECh. 11 - Prob. 23PECh. 11 - Prob. 24PECh. 11 - Prob. 25PECh. 11 - Prob. 26PECh. 11 - Prob. 27PECh. 11 - Prob. 28PECh. 11 - Prob. 29PECh. 11 - Prob. 30PECh. 11 - Prob. 31PECh. 11 - Prob. 32PECh. 11 - Prob. 33PECh. 11 - Prob. 34PECh. 11 - Prob. 35PECh. 11 - Prob. 36PECh. 11 - Prob. 37PECh. 11 - Prob. 38PECh. 11 - Prob. 39PECh. 11 - Prob. 40PECh. 11 - Prob. 47PECh. 11 - Prob. 48PECh. 11 - Prob. 49PECh. 11 - Prob. 50PECh. 11 - Prob. 51PECh. 11 - Prob. 52PECh. 11 - Prob. 55AECh. 11 - Prob. 56AECh. 11 - Prob. 57AECh. 11 - Prob. 58AECh. 11 - Prob. 59AECh. 11 - Prob. 63AECh. 11 - Prob. 64AECh. 11 - Prob. 65AECh. 11 - Prob. 66AECh. 11 - Prob. 67AECh. 11 - Prob. 68AECh. 11 - Prob. 76AECh. 11 - Prob. 77AECh. 11 - Prob. 78AECh. 11 - Prob. 81AECh. 11 - Prob. 82AECh. 11 - Prob. 83AECh. 11 - Prob. 84AECh. 11 - Prob. 85AECh. 11 - Prob. 86AECh. 11 - Prob. 87AECh. 11 - Prob. 88CECh. 11 - Prob. 89CECh. 11 - Prob. 90CECh. 11 - Prob. 92CECh. 11 - Prob. 93CECh. 11 - Prob. 94CECh. 11 - Prob. 95CE
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- What main factors control the magnitude of lattice energies? Give a specific example of a compound that should have a high lattice energy, and explain why its lattice energy is high.arrow_forwardhat does temperature measure? Are the molecules in a beaker of warm water moving at the same speed as the molecules in a beaker of cold water? Explain? What is heat? Is heat the same as temperature?arrow_forwardName the type of bond that is formed when electrons are shared between two atoms. a.shared bond b.ionic bond c.covalent bond d.multiple bondarrow_forward
- What is the most polar bond in the molecule?arrow_forwardWrite the Lewis structure for nitrosyl fluoride, FNO. Using only a periodic table, identify (a) which is the longer bond. (b) which is the stronger bond. (c) which is the more polar bond.arrow_forwardUsing Lewis Structures to Determine the Correct Chemical Formula for Ionic Compounds Use Lewis structures to determine the correct chemical formula for the compound formed between LiandO.arrow_forward
- Represent the following molecules by Lewis structures: a. CH4 each H atom is bonded to the C atom b. CO2 each O atom is bonded to the C atom c. H2Se each H atom is bonded to the Se atom d. NH3 the H atom is bonded to the N atomarrow_forwardBond Enthalpy When atoms of the hypothetical element X are placed together, they rapidly undergo reaction to form the X2 molecule: X(g)+X(g)X2(g) a Would you predict that this reaction is exothermic or endothermic? Explain. b Is the bond enthalpy of X2 a positive or a negative quantity? Why? c Suppose H for the reaction is 500 kJ/mol. Estimate the bond enthalpy of the X2 molecule. d Another hypothetical molecular compound, Y2(g), has a bond enthalpy of 750 kJ/mol, and the molecular compound XY(g) has a bond enthalpy of 1500 kJ/mol. Using bond enthalpy information, calculate H for the following reaction. X2(g)+Y2(g)2XY(g) e Given the following information, as well as the information previously presented, predict whether or not the hypothetical ionic compound AX is likely to form. In this compound, A forms the A+ cation, and X forms the X anion. Be sure to justify your answer. Reaction: A(g)+12X2(g)AX(s)The first ionization energy of A(g) is 400 kJ/mol. The electron affinity of X(g) is 525 kJ/mol. The lattice energy of AX(s) is 100 kJ/mol. f If you predicted that no ionic compound would form from the reaction in Part e, what minimum amount of AX(s) lattice energy might lead to compound formation?arrow_forwardExplain the difference between a nonpolar covalent bond, a polar covalent bond, and an ionic bond.arrow_forward
- Which statements are true about electronegativity? (a) Electronegativity increases from left to right in a period of the Periodic Table. (b) Electronegativity increases from top to bottom in a column of the Periodic Table. (c) Hydrogen, the element with the lowest atomic number, has the smallest electronegativity. (d) The higher the atomic number of an element, the greater its electronegativity.arrow_forwardMethylcyanoacrylate is the active ingredient in super glues. Its Lewis structure is In this molecule, which is the (a) weakest carbon-containing bond? (b) strongest carbon-containing bond? (c) most polar bond?arrow_forwardUse the References to access important values if needed for this question. Use average bond enthalpies (linked above) to calculate the enthalpy change for the following gas-phase reaction. 2HBr(g) + Cl₂(g) → 2HCI(g) + Br₂(0) To analyze the reaction, first draw Lewis structures for all reactant and product molecules. Draw the reaction using separate sketchers for each species. • Separate multiple reactants and/or products using the + sign from the drop-down arrow. . Separate reactants from products using the symbol from the drop-down menu. Remember to include nonbonding valence electrons in your Lewis structures. 0- ♥ / 4 IFarrow_forward
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