Chapter 11, Problem 91A

To determine

Speed of the ball when it leaves the tee.

Answer to Problem 91A

  $36.39\text{ m/s}$

Explanation of Solution

Given:

Mass of golf ball, $m_1=0.046\text{ kg}$

Mass of golf club, $m_2=0.220\text{ kg}$

Speed of golf club, $v_2=44\text{ m/s}$

Formula Used:

According to conservation of momentum.

Momentum before collision will be equal to momentum after collision.

  $p_i=p_f$

Calculations:

As the golf ball is at rest before the collision.

Therefore, speed of golf ball before collision $v_1=0\text{ m/s}$

Therefore,

  $\begin{array}{l}{m}_1{v}_1+m_2{v}_2=\left(m_1+m_2\right)v\\ 0.046\times 0+0.220\times 44=\left(0.046+0.220\right)v\\ 0.266v=9.68\\ v=36.39\text{ m/s}\end{array}$

Conclusion:

Therefore, speed of the ball when it leaves the tee is $36.39\text{ m/s}$ .