Chapter 11, Problem 52A

To determine

The mass of the block if the display indicates that $1.00\text{J}$ of work is done.

Answer to Problem 52A

  $0.102\text{}\text{kg}$

Explanation of Solution

Given:

The distance up to which block is lifted, $\Delta h=1.00\text{m}$

Formula used:

The work done on any object is equal to the difference in the energy of the object,

  $W=\Delta E$

And, the gravitational potential energy of an object which is at a height $h$ from the surface is given by,

  $PE=mgh$

Calculation:

Since the block is not having any velocity, thus only energy it is having is the gravitational potential energy.

Then,

  $\begin{array}{c}W=\Delta PE\\ =mg\Delta h\end{array}$

Where $m$ is the mass of the block.

Using the given values in above,

  $\begin{array}{c}W=\Delta E\\ 1.0=m\left(9.8\right)\left(1.0\right)\\ m=0.102\text{}\text{kg}\end{array}$

Conclusion:

Thus, the mass of the block is $0.102\text{}\text{kg}$ .