A point in three-dimensional space can be represented in a three-dimensional coordinate system . In such a case, a z -axis is taken perpendicular to both the x - and y -axes . A point P is assigned an ordered triple P x , y , z relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula d = x 2 − x 1 2 + y 2 − y 1 2 + z 2 − z 1 2 . 6 , − 4 , − 1 and 2 , 3 , 1
A point in three-dimensional space can be represented in a three-dimensional coordinate system . In such a case, a z -axis is taken perpendicular to both the x - and y -axes . A point P is assigned an ordered triple P x , y , z relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula d = x 2 − x 1 2 + y 2 − y 1 2 + z 2 − z 1 2 . 6 , − 4 , − 1 and 2 , 3 , 1
Solution Summary: The author explains the formula for the distance between the two points (6,-4,-1) and
A point in three-dimensional space can be represented in a three-dimensional coordinate system. In such a case, a
z
-axis
is taken perpendicular to both the
x
- and
y
-axes
.
A point
P
is assigned an ordered triple
P
x
,
y
,
z
relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula
d
=
x
2
−
x
1
2
+
y
2
−
y
1
2
+
z
2
−
z
1
2
.
6
,
−
4
,
−
1
and
2
,
3
,
1
System that uses coordinates to uniquely determine the position of points. The most common coordinate system is the Cartesian system, where points are given by distance along a horizontal x-axis and vertical y-axis from the origin. A polar coordinate system locates a point by its direction relative to a reference direction and its distance from a given point. In three dimensions, it leads to cylindrical and spherical coordinates.
Suppose that a particle moves along a straight line with velocity v (t) = 62t, where 0 < t <3 (v(t)
in meters per second, t in seconds). Find the displacement d (t) at time t and the displacement up to
t = 3.
d(t)
ds
= ["v (s) da = {
The displacement up to t = 3 is
d(3)-
meters.
Let f (x) = x², a 3, and b
=
=
4.
Answer exactly.
a. Find the average value fave of f between a and b.
fave
b. Find a point c where f (c) = fave. Enter only one of the possible values for c.
c=
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