Elementary Statistics (13th Edition)
13th Edition
ISBN: 9780134462455
Author: Mario F. Triola
Publisher: PEARSON
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Chapter 11, Problem 7CRE
Car Repair Costs Listed below are repair costs (in dollars) for cars crashed at 6 mi/h in full-front crash tests and the same cars crashed at 6 mi/h in full-rear crash tests (based on data from the Insurance Institute for Highway Safety). The cars are the Toyota Camry, Mazda 6, Volvo $40, Saturn Aura, Subaru Legacy. Hyundai Sonata, and Honda Accord. Is there sufficient evidence to conclude that there is a
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2.2, 13.2-13.3)
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The accompanying table contains the data for the amounts (in oz) in cans of a certain soda. The cans are labeled to indicate that the contents are 20 oz of soda. Use the sign test and
0.05 significance level to test the claim that cans of this soda are filled so that the median amount is 20 oz. If the median is not 20 oz, are consumers being cheated?
Click the icon to view the data.
What are the null and alternative hypotheses?
OA. Ho: Medi
More Info
H₁: Medi
OC. Ho: Medi
H₁: Medi
Volume (in ounces)
20.3
20.1
20.4
Find the test stat
20.1
20.5
20.1
20.1
19.9
20.1
Test statistic =
20.2
20.3
20.3
20.1
20.4
20.5
Find the P-value
19.7
20.2
20.4
20.1
20.2
20.2
P-value=
(R
19.9
20.1
20.5
20.4
20.1
20.4
Determine the p
20.1
20.3
20.4
20.2
20.3
20.4
Since the P-valu
19.9
20.2
19.9
Print
Done
20 oz
20 oz
20 oz
20 oz
ce that the consumers are being cheated.
T
Teenage obesity (O), and weekly fast-food meals (F), among some selected Mississippi teenagers are:
Name Obesity (lbs) # of Fast-foods per week
Josh
185
10
Karl
172
8
Terry
168
9
Kamie
Andy
204
154
12
6
(a) Compute the variance of Obesity, s²o, and the variance of fast-food meals, s², of this data. [Must show full work].
(b) Compute the Correlation Coefficient between O and F. [Must show full work].
(c) Find the Coefficient of Determination between O and F. [Must show full work].
(d) Obtain the Regression equation of this data. [Must show full work].
(e) Interpret your answers in (b), (c), and (d). (Full explanations required).
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?
Chapter 11 Solutions
Elementary Statistics (13th Edition)
Ch. 11.1 - Cybersecurity The table below lists leading digits...Ch. 11.1 - 2. Cybersecurity When using the data from Exercise...Ch. 11.1 - Cybersecurity The accompanying Statdisk results...Ch. 11.1 - Cybersecurity What do the results from the...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...
Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - In Exercises 520, conduct the hypothesis test and...Ch. 11.1 - Ben fords Law. According to Benfords law, a...Ch. 11.1 - Ben fords Law. According to Benfords law, a...Ch. 11.1 - Ben fords Law. According to Benfords law, a...Ch. 11.1 - Ben fords Law. According to Benfords law, a...Ch. 11.1 - Assumed mid-point x=fxn=39825180=221.25...Ch. 11.2 - Handedness and Cell Phone Use The accompanying...Ch. 11.2 - Ear Preference for Cell Phone Use 2. Hypotheses...Ch. 11.2 - Hypothesis Test The accompanying TI-83/84 Plus...Ch. 11.2 - Right-Tailed, Left-Tailed, Two-Tailed Is the...Ch. 11.2 - Prob. 5BSCCh. 11.2 - In Exercises 5-18, test the given claim. 6. Splint...Ch. 11.2 - In Exercises 5-18, test the given claim. 7....Ch. 11.2 - Prob. 8BSCCh. 11.2 - In Exercises 5-18, test the given claim. 9. Four...Ch. 11.2 - In Exercises 5-18, test the given claim. 10....Ch. 11.2 - In Exercises 5-18, test the given claim. 11....Ch. 11.2 - In Exercises 5-18, test the given claim. 12. Nurse...Ch. 11.2 - Soccer Strategy In soccer, serious fouls in the...Ch. 11.2 - In Exercises 5-18, lest the given claim. 14. Is...Ch. 11.2 - In Exercises 518, test the given claim. 15....Ch. 11.2 - In Exercises 5-18, test the given claim. 16....Ch. 11.2 - Prob. 17BSCCh. 11.2 - In Exercises 5-18, test the given claim. 18....Ch. 11.2 - In Exercises 5-18, lest the given claim. 19. Car...Ch. 11.2 - Is the Home Field Advantage Independent of the...Ch. 11.2 - Equivalent Tests A X2 test involving a 2 2 table...Ch. 11.2 - Using Yatess Correction for Continuity The...Ch. 11 - Exercises 1-5 refer to the sample data in the...Ch. 11 - Exercises 15 refer to the sample data in the...Ch. 11 - Exercises 15 refer to the sample data in the...Ch. 11 - Prob. 4CQQCh. 11 - Exercises 15 refer to the sample data in the...Ch. 11 - Questions 610 refer to the sample data in the...Ch. 11 - Questions 610 refer to the sample data in the...Ch. 11 - Questions 6-10 refer to the sample data in the...Ch. 11 - Find the number of degrees of freedom.Ch. 11 - Questions 6-10 refer to the sample data in the...Ch. 11 - Motor Vehicle Fatalities The table below lists...Ch. 11 - Tooth Fillings The table below shows results from...Ch. 11 - American Idol Contestants on the TV show American...Ch. 11 - Clinical Trial of Lipitor Lipitor is the trade...Ch. 11 - Weather-Related Deaths For a recent year, the...Ch. 11 - Weather-Related Deaths Review Exercise 5 involved...Ch. 11 - Chocolate and Happiness In a survey sponsored by...Ch. 11 - Chocolate and Happiness Use the results from part...Ch. 11 - Chocolate and Happiness Use the results from part...Ch. 11 - One Big Bill or Many Smaller Bills In a study of...Ch. 11 - 6. Probability Refer to the results from the 150...Ch. 11 - Car Repair Costs Listed below are repair costs (in...Ch. 11 - Forward Grip Reach and Ergonomics When designing...Ch. 11 - Use Statdisk, Minitab, Excel, StatCrunch, a...Ch. 11 - FROM DATA TO DECISION Critical Thinking: Was...
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- A special interest group reports a tiny margin of error (plus or minus 0.04 percent) for its online survey based on 50,000 responses. Is the margin of error legitimate? (Assume that the group’s math is correct.)arrow_forwardSuppose that 73 percent of a sample of 1,000 U.S. college students drive a used car as opposed to a new car or no car at all. Find an 80 percent confidence interval for the percentage of all U.S. college students who drive a used car.What sample size would cut this margin of error in half?arrow_forwardYou want to compare the average number of tines on the antlers of male deer in two nearby metro parks. A sample of 30 deer from the first park shows an average of 5 tines with a population standard deviation of 3. A sample of 35 deer from the second park shows an average of 6 tines with a population standard deviation of 3.2. Find a 95 percent confidence interval for the difference in average number of tines for all male deer in the two metro parks (second park minus first park).Do the parks’ deer populations differ in average size of deer antlers?arrow_forward
- Suppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forwardA random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forwardSuppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forward
- Is it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forwardTines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forwardBased on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forward
- A 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forwardDescribe the situation in which Fisher’s exact test would be used?(ii) When do we use Yates’ continuity correction (with respect to contingencytables)?[2 Marks] 2. Investigate, checking the relevant assumptions, whether there is an associationbetween age group and home ownership based on the sample dataset for atown below:Home Owner: Yes NoUnder 40 39 12140 and over 181 59Calculate and evaluate the effect size.arrow_forward
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