Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
expand_more
expand_more
format_list_bulleted
Question
Chapter 11, Problem 63AE
Interpretation Introduction
Interpretation:
The reason for
Concept Introduction:
Determination of shape using VSEPR theory:
- 1) The Lewis structure of the molecule is drawn.
The representation of valence shell electrons around the atom is known as Lewis structure or Lewis dot structure. Electrons are represented as a dot in Lewis structures, a single dot represents unpaired electron and paired of dots represents paired electrons.
- 2) The electron pairs surrounding the central atom are counted and the electron pairs are arranged with minimum repulsion. Thus arrangements of electron pairs are determined.
- 3) The positions of other atoms are determined.
- 4) The molecular structure is then identified.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
In general terms, how does each of the following atomic properties influence the metallic character of the main-group elements in a period?(a) Ionization energy(b) Atomic radius(c) Number of outer electrons(d) Effective nuclear charge
Element X is a metal with a valency 2. Element Y is a non-metal with a valency 3
(a) Write equations to show how X and Y form ions.
(b) If Y is a diatomic gas, write the equation for the direct combination of X and Y to form a
compound.
Choosing from the elements in the third row of the Periodic Table write out thechemical formula of(i) A basic oxide.(ii) An amphoteric oxide.(iii) An acidic oxide
Chapter 11 Solutions
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Ch. 11.1 - Prob. 11.1PCh. 11.2 - Prob. 11.2PCh. 11.3 - Prob. 11.3PCh. 11.4 - Prob. 11.4PCh. 11.4 - Prob. 11.5PCh. 11.5 - Prob. 11.6PCh. 11.6 - Prob. 11.7PCh. 11.6 - Prob. 11.8PCh. 11.7 - Prob. 11.9PCh. 11.8 - Prob. 11.10P
Ch. 11.9 - Prob. 11.11PCh. 11.10 - Prob. 11.12PCh. 11 - Prob. 1RQCh. 11 - Prob. 2RQCh. 11 - Prob. 3RQCh. 11 - Prob. 4RQCh. 11 - Prob. 5RQCh. 11 - Prob. 6RQCh. 11 - Prob. 7RQCh. 11 - Prob. 8RQCh. 11 - Prob. 9RQCh. 11 - Prob. 10RQCh. 11 - Prob. 11RQCh. 11 - Prob. 12RQCh. 11 - Prob. 13RQCh. 11 - Prob. 14RQCh. 11 - Prob. 15RQCh. 11 - Prob. 16RQCh. 11 - Prob. 17RQCh. 11 - Prob. 18RQCh. 11 - Prob. 19RQCh. 11 - Prob. 20RQCh. 11 - Prob. 21RQCh. 11 - Prob. 22RQCh. 11 - Prob. 23RQCh. 11 - Prob. 24RQCh. 11 - Prob. 25RQCh. 11 - Prob. 26RQCh. 11 - Prob. 28RQCh. 11 - Prob. 30RQCh. 11 - Prob. 31RQCh. 11 - Prob. 33RQCh. 11 - Prob. 36RQCh. 11 - Prob. 1PECh. 11 - Prob. 2PECh. 11 - Prob. 3PECh. 11 - Prob. 4PECh. 11 - Prob. 5PECh. 11 - Prob. 6PECh. 11 - Prob. 7PECh. 11 - Prob. 8PECh. 11 - Prob. 9PECh. 11 - Prob. 10PECh. 11 - Prob. 11PECh. 11 - Prob. 12PECh. 11 - Prob. 13PECh. 11 - Prob. 14PECh. 11 - Prob. 15PECh. 11 - Prob. 16PECh. 11 - Prob. 17PECh. 11 - Prob. 18PECh. 11 - Prob. 19PECh. 11 - Prob. 20PECh. 11 - Prob. 21PECh. 11 - Prob. 22PECh. 11 - Prob. 23PECh. 11 - Prob. 24PECh. 11 - Prob. 25PECh. 11 - Prob. 26PECh. 11 - Prob. 27PECh. 11 - Prob. 28PECh. 11 - Prob. 29PECh. 11 - Prob. 30PECh. 11 - Prob. 31PECh. 11 - Prob. 32PECh. 11 - Prob. 33PECh. 11 - Prob. 34PECh. 11 - Prob. 35PECh. 11 - Prob. 36PECh. 11 - Prob. 37PECh. 11 - Prob. 38PECh. 11 - Prob. 39PECh. 11 - Prob. 40PECh. 11 - Prob. 47PECh. 11 - Prob. 48PECh. 11 - Prob. 49PECh. 11 - Prob. 50PECh. 11 - Prob. 51PECh. 11 - Prob. 52PECh. 11 - Prob. 55AECh. 11 - Prob. 56AECh. 11 - Prob. 57AECh. 11 - Prob. 58AECh. 11 - Prob. 59AECh. 11 - Prob. 63AECh. 11 - Prob. 64AECh. 11 - Prob. 65AECh. 11 - Prob. 66AECh. 11 - Prob. 67AECh. 11 - Prob. 68AECh. 11 - Prob. 76AECh. 11 - Prob. 77AECh. 11 - Prob. 78AECh. 11 - Prob. 81AECh. 11 - Prob. 82AECh. 11 - Prob. 83AECh. 11 - Prob. 84AECh. 11 - Prob. 85AECh. 11 - Prob. 86AECh. 11 - Prob. 87AECh. 11 - Prob. 88CECh. 11 - Prob. 89CECh. 11 - Prob. 90CECh. 11 - Prob. 92CECh. 11 - Prob. 93CECh. 11 - Prob. 94CECh. 11 - Prob. 95CE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Each of the chemically active Period 2 elements forms sta-ble compounds that have bonds to fluorine.(a) What are the names and formulas of these compounds?(b) Does ΔEN increase or decrease left to right across the period?(c) Does percent ionic character increase or decrease left to right?(d) Draw Lewis structures for these compounds.arrow_forwardThe elements sodium, aluminum, and chlorine are in the same period. (a) Which has the greatest electronegativity? (b) Which of the atoms is smallest? (c) Which is the largest possible oxidation state for each of these elements? (d) Will the oxide of each element in the highest oxidation state (write its formula) be acidic, basic, or amphoteric?arrow_forwardIndicate the physical state for each of the following elements at 25 °C and normal pressure. Classify each element as a metal, nonmetal, or semimetal: (a) barium (b) boron (c)bismuth (d) brominearrow_forward
- (a) List four physical characteristics of a solid metal. (b) List two chemical characteristics of a metallic element.arrow_forwardWrite the electron configuration and orbital diagram for each ion and predict whether each will be paramagnetic or diamagnetic.(a) Co2+ (b) N3- (c) Ca2+arrow_forwardGive the group number and the general valence electron configuration of an element with the following electron-dot symbol. (For example, type ns2 np6 for ns²np°, which is the valence configuration of all group 8A elements.) (a) group number electron configuration (b) group number electron configurationarrow_forward
- Given the following elements: Si, Sr, Cu, Ti, S (a) which of those elements would have the larget atomic radius? (b) which of those elements would have the highest ionization energy? (c) which of those elements would have the lowest electronegativity?arrow_forwardEnergy is required to remove two electrons from Ca to formCa2+, and energy is required to add two electrons to O toform O2 - . Yet CaO is stable relative to the free elements.Which statement is the best explanation? (a) The latticeenergy of CaO is large enough to overcome these processes.(b) CaO is a covalent compound, and these processes areirrelevant. (c) CaO has a higher molar mass than either Ca orO. (d) The enthalpy of formation of CaO is small. (e) CaO isstable to atmospheric conditions.arrow_forwardPlease answer the question below in DETAIL.arrow_forward
- Complete and balance the following equations. Write the entire equation, including the reactants and products, and include the physical state of each species. (a) Na(s) + O2(g)→ (b) K(s) + O2(g)→arrow_forwardConsider the elements O, Ba, Co, Be, Br, and Se. From this list,select the element that (a) is most electronegative, (b) exhibitsa maximum oxidation state of +7, (c) loses an electronmost readily, (d) forms π bonds most readily, (e) is a transitionmetal, (f) is a liquid at room temperature and pressure.arrow_forwardThe first three ionization energies of an element X are 900, 1745, and 14912 kJ·mol–1. What is the most likely formula for the stable ion of X?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Periodic Properties of Elements | Chemistry | IIT-JEE | NEET | CBSE | Misostudy; Author: Misostudy;https://www.youtube.com/watch?v=L26rRWz4_AI;License: Standard YouTube License, CC-BY
Periodic Trends: Electronegativity, Ionization Energy, Atomic Radius - TUTOR HOTLINE; Author: Melissa Maribel;https://www.youtube.com/watch?v=0h8q1GIQ-H4;License: Standard YouTube License, CC-BY