Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
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Question
Chapter 11, Problem 15RQ
Interpretation Introduction
Interpretation:
The Lewis structure of
Concept Introduction:
Lewis structure:
The representation of valence shell electrons around the atom is known as Lewis structure or Lewis dot structure. Electrons are represented as a dot in Lewis structures, a single dot represents unpaired electron and paired of dots represents paired electrons.
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Check out a sample textbook solutionStudents have asked these similar questions
Calcium (Ca) has a greater electronegativity than Barium (Ba). Explain why.
In your explanation discuss the atom's structure: energy levels (rings), protons, and/or
valence electrons.
This Lewis Structure is incorrect because
[Ca]+ [:O:]-
The metal should be negative and the
nonmetal should be positive
The metal should have a +2 charge and
the nonmetal should have a -2 charge
The metal should have 2 electrons
O around it and the nonmetal should have 6
electrons around it
There is nothing wrong with the Lewis
Structure
2.
Aa.110.
Chapter 11 Solutions
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Ch. 11.1 - Prob. 11.1PCh. 11.2 - Prob. 11.2PCh. 11.3 - Prob. 11.3PCh. 11.4 - Prob. 11.4PCh. 11.4 - Prob. 11.5PCh. 11.5 - Prob. 11.6PCh. 11.6 - Prob. 11.7PCh. 11.6 - Prob. 11.8PCh. 11.7 - Prob. 11.9PCh. 11.8 - Prob. 11.10P
Ch. 11.9 - Prob. 11.11PCh. 11.10 - Prob. 11.12PCh. 11 - Prob. 1RQCh. 11 - Prob. 2RQCh. 11 - Prob. 3RQCh. 11 - Prob. 4RQCh. 11 - Prob. 5RQCh. 11 - Prob. 6RQCh. 11 - Prob. 7RQCh. 11 - Prob. 8RQCh. 11 - Prob. 9RQCh. 11 - Prob. 10RQCh. 11 - Prob. 11RQCh. 11 - Prob. 12RQCh. 11 - Prob. 13RQCh. 11 - Prob. 14RQCh. 11 - Prob. 15RQCh. 11 - Prob. 16RQCh. 11 - Prob. 17RQCh. 11 - Prob. 18RQCh. 11 - Prob. 19RQCh. 11 - Prob. 20RQCh. 11 - Prob. 21RQCh. 11 - Prob. 22RQCh. 11 - Prob. 23RQCh. 11 - Prob. 24RQCh. 11 - Prob. 25RQCh. 11 - Prob. 26RQCh. 11 - Prob. 28RQCh. 11 - Prob. 30RQCh. 11 - Prob. 31RQCh. 11 - Prob. 33RQCh. 11 - Prob. 36RQCh. 11 - Prob. 1PECh. 11 - Prob. 2PECh. 11 - Prob. 3PECh. 11 - Prob. 4PECh. 11 - Prob. 5PECh. 11 - Prob. 6PECh. 11 - Prob. 7PECh. 11 - Prob. 8PECh. 11 - Prob. 9PECh. 11 - Prob. 10PECh. 11 - Prob. 11PECh. 11 - Prob. 12PECh. 11 - Prob. 13PECh. 11 - Prob. 14PECh. 11 - Prob. 15PECh. 11 - Prob. 16PECh. 11 - Prob. 17PECh. 11 - Prob. 18PECh. 11 - Prob. 19PECh. 11 - Prob. 20PECh. 11 - Prob. 21PECh. 11 - Prob. 22PECh. 11 - Prob. 23PECh. 11 - Prob. 24PECh. 11 - Prob. 25PECh. 11 - Prob. 26PECh. 11 - Prob. 27PECh. 11 - Prob. 28PECh. 11 - Prob. 29PECh. 11 - Prob. 30PECh. 11 - Prob. 31PECh. 11 - Prob. 32PECh. 11 - Prob. 33PECh. 11 - Prob. 34PECh. 11 - Prob. 35PECh. 11 - Prob. 36PECh. 11 - Prob. 37PECh. 11 - Prob. 38PECh. 11 - Prob. 39PECh. 11 - Prob. 40PECh. 11 - Prob. 47PECh. 11 - Prob. 48PECh. 11 - Prob. 49PECh. 11 - Prob. 50PECh. 11 - Prob. 51PECh. 11 - Prob. 52PECh. 11 - Prob. 55AECh. 11 - Prob. 56AECh. 11 - Prob. 57AECh. 11 - Prob. 58AECh. 11 - Prob. 59AECh. 11 - Prob. 63AECh. 11 - Prob. 64AECh. 11 - Prob. 65AECh. 11 - Prob. 66AECh. 11 - Prob. 67AECh. 11 - Prob. 68AECh. 11 - Prob. 76AECh. 11 - Prob. 77AECh. 11 - Prob. 78AECh. 11 - Prob. 81AECh. 11 - Prob. 82AECh. 11 - Prob. 83AECh. 11 - Prob. 84AECh. 11 - Prob. 85AECh. 11 - Prob. 86AECh. 11 - Prob. 87AECh. 11 - Prob. 88CECh. 11 - Prob. 89CECh. 11 - Prob. 90CECh. 11 - Prob. 92CECh. 11 - Prob. 93CECh. 11 - Prob. 94CECh. 11 - Prob. 95CE
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- An ionic compound has the following composition (by mass): Mg, 10.9%; Cl, 31.8%; O, 57.3%. What are the formula and name of the compound? Write the Lewis formulas for the ions.arrow_forwardAn ionic compound has the following composition (by mass): Ca, 30.3%; N, 21.2%; O, 48.5%. What are the formula and name of the compound? Write the Lewis formulas for the ions.arrow_forwardWrite the steps (reactions) for the Born-Haber cycle for MgCl2(s). Use the Born-Haber cycle to calculate the lattice energy of MgCl2(s). Some useful data to work with: For Mg: ΔΔHsub = 147 kJ/mol, IE1 and IE2 are 738 kJ/mol and 1450 kJ/mol, respectively. For chlorine: Bond energy = 243 kJ/mol, EA1 = -349 kJ/mol, respectively. The enthalpy of formation of magnesium chloride is -748.8 kJ/mol.arrow_forward
- The following Lewis diagram represents the valence electron configuration of a main-group element. This element is in group [VIIA(17) According to the octet rule, this element would be expected to form an ion with a charge of 1- If X is in period 4, the ion formed has the same electron configuration as the noble gas The symbol for the ion isarrow_forwardThe following Lewis diagram represents the valence electron configuration of a main-group element. X• If this element is in period 2, its valence electron configuration is |arrow_forwardThe information provided for the first question is not an option.arrow_forward
- Calculate the lattice energy of NaCl(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Na(s) ΔHsublimation = 88 kJ/mol Na(g) Ionization energy = 476 kJ/mol Cl-Cl(g) Bond energy = 223 kJ/mol Cl(g) Electron affinity = -369 kJ/mol NaCl(s) ΔH°f = -431 kJ/mol ____________ kJ/molarrow_forwardMark each statement as True (T) or False (F). i) CO belongs to the binary ionic compounds. ii) Reaction between N2 and H2 gives NH3 and H2O. iii) Modern periodic table is based on atomic weight (mass number). iv) In a group, elements have similar chemical properties. v) Size of an atom is larger as compared to the size of the nucleus. vi) Alpha rays are deflected back due to the presence of electrons in an atomarrow_forward1) What do you predict the average bond length and average bond energy values for the F-F bond based on the chart below? WIll it be higher than, lower than, or the same as the other bonds shown in the chart. Justify your answer. Bond Average Bond Length (PM) Average Bond Energy (KJ/MOLE) CL-CL 199 243 Br-Br 228 193 I-I 267 151 2) Explain how a stable covalent bond is formed in terms of attractive and repulsive forces. Note: Please briefly explain, Thank you.arrow_forward
- Please don't provide handwritten solution...arrow_forwardThe chemical formula for the compound that forms between sodium and chlorine is NaCl, while the compound that forms between magnesium and chlorine is MgCl2. Explain this difference using the octet rule and the Lewis Dot Diagrams for each particle (Na, Cl, & Mg).arrow_forwardU is a made up element and contains 5 valence electrons E is a made up element and contains 6 valence electrons 1. Calculate the total valence electrons does UE, (1 pt) 2. Draw the Lewis structure of UE, (5 pt) 3. UE, is considered a highly reactive chemical. Using your knowledge of Lewis structure, explain why that is?arrow_forward
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