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Concept explainers
(a)
Interpretation:
The given sugar pair (D-glyceraldehyde and dihydroxyacetone)
should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. Anomers are the glycosides or cyclic monosaccharides that are epimers. These are different from each other in the configuration of C-1 (aldoses) or at C-2 if (ketoses).
(b)
Interpretation:
The given sugar pair should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. These are comprised of hydrogen and oxygen in a similar ratio as in water (2:1). They are usually broken down to release the energy in the animal body. These are of three types: monosaccharides, disaccharides, and polysaccharides.
(c)
Interpretation:
The given sugar pair (D-glucose and D-fructose) should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. These are comprised of hydrogen and oxygen in a similar ratio as in water (2:1). They are usually broken down to release the energy in the animal body. These are of three types: monosaccharides, disaccharides, and polysaccharides.
(d)
Interpretation:
The given sugar pair (a-D-glucose and β-D-glucose) should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. These are comprised of hydrogen and oxygen in a similar ratio as in water (2:1). They are usually broken down to release the energy in the animal body. These are of three types: monosaccharides, disaccharides, and polysaccharides.
(e)
Interpretation:
The given sugar pair (D-ribose and D-ribulose) should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. These are comprised of hydrogen and oxygen in a similar ratio as in water (2:1). They are usually broken down to release the energy in the animal body. These are of three types: monosaccharides, disaccharides, and polysaccharides.
(f)
Interpretation:
The given sugar pair (D-galactose and D-glucose) should be determined.
Concept introduction:
Carbohydrates are a large group of organic compounds that are present in foods, living tissues. These include sugars, cellulose, and starch. These are comprised of hydrogen and oxygen in a similar ratio as in water (2:1). They are usually broken down to release the energy in the animal body. These are of three types: monosaccharides, disaccharides, and polysaccharides.
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Chapter 11 Solutions
Biochemistry
- Show a mechanism that leads to the opening of the ring below under acid-catalyzed conditions. Give the correct Fischer projection for this sugar.arrow_forwardWhat is the stereochemical relationship between B & C?arrow_forwardDon't use ai or any chat gpt will dislike okk just use accurate information okkk okkk just solve full accurate. don't use guidelines okk just did it accurate 100% sure experts solve it correct complete solutions okkk follow all instructions requirements okkkarrow_forward
- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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