Engineering Fundamentals: An Introduction to Engineering
6th Edition
ISBN: 9780357112311
Author: Saeed Moaveni
Publisher: Cengage Learning US
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Chapter 11, Problem 20P
To determine
Find the temperature rise in aluminum plate after 10 seconds.
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The tension member shown in the figure below must resist a service dead load of 60 kips and a service live load of 45 kips. Does the member have
enough strength? The steel is A588: Fy = 50 ksi, F₁ = 70 ksi; and the bolts are 11/8 inches in diameter. Assume that A = An
PL 38 x 72
оо
a. Use LRFD.
Determine the design strength and the factored load. Make a conclusion about the member.
(Express your answers to three significant figures.)
+Pn
Pu
=
=
kips
kips
-Select-
b. Use ASD.
Determine the allowable strength and required strength. Make a conclusion about the member.
(Express your answers to three significant figures.)
Ft Ae
=
P₁ =
-Select-
kips
kips
A single-angle tension member of A36 steel must resist a dead load of 49 kips and a live load of 84 kips. The length of the member is 18 feet, and
it will be connected with a single line of 1-inch-diameter bolts, as shown in the figure below. There will be four or more bolts in this line. For the steel
Fy = 36 ksi and F₁ = 58 ksi. Try the tension members given in the table below.
Tension member
4, (in.)
rz (in.)
7
L6 × 6 ×
9.75
1.17
8
L 5 × 3
×
4.93
0.746
L 5 × 3
×
5
2.56
0.758
16
7
L5 × 3 ×
3.31
0.644
16
Bolt line
a. Select a single-angle tension member to resist the loads. Use LRFD.
A) L 6 × 6 ×
B) L 5 × 3 ×
CL5×3×
D) L 5 × 3 ×
-Select-
5
16
7
16
What is the required gross area?
(Express your answer to three significant figures.)
A₁ =
in.²
What is the required effective area?
(Express your answer to three significant figures.)
A =
in.2
What is the minimum radius of gyration?
(Express your answer to three significant figures.)
"min =
in.
b. Select a single-angle tension member to…
An L6 × 4 × 5/8 tension member of A36 steel is connected to a gusset plate with 1-inch-diameter bolts, as shown in the
figure below. It is subjected to the following service loads: dead load = 40 kips, live load = 100 kips, and wind load
= 45 kips. Use the equation for U: U = 1 −
For A36 steel: Fy = 36 ksi, F = 58 ksi.
x
l
For L6 × 4×5/8: Ag = 5.86 in.², x = 1.03 in.
21/4"
L6 × 4 × 5/8
11/2"
21/2"
11/2"
a. Determine whether this member is adequate using LRFD.
-Select-
What is the design strength for LFRD?
(Express your answer to three significant figures.)
Φι Ρη -
=
kips
Which AISC load combination controls?
-Select-
What is the controlling AISC load combination?
(Express your answer to three significant figures.)
Pu
=
kips
b. Determine whether this member is adequate using ASD.
-Select-
What is the allowable strength for ASD?
(Express your answer to three significant figures.)
Pn
Sit
kips
Which ASD load combination controls?
-Select-
What is the controlling ASD load combination?…
Chapter 11 Solutions
Engineering Fundamentals: An Introduction to Engineering
Ch. 11.2 - Prob. 1BYGCh. 11.2 - Prob. 2BYGCh. 11.2 - Prob. 3BYGCh. 11.2 - Prob. 4BYGCh. 11.2 - Prob. 5BYGCh. 11.2 - Prob. BYGVCh. 11.4 - Prob. 1BYGCh. 11.4 - Prob. 2BYGCh. 11.4 - Prob. 3BYGCh. 11.4 - Prob. 4BYG
Ch. 11.4 - Prob. BYGVCh. 11.6 - Prob. 1BYGCh. 11.6 - Prob. 2BYGCh. 11.6 - Prob. 3BYGCh. 11.6 - Prob. 4BYGCh. 11.6 - Prob. BYGVCh. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Alcohol thermometers can measure temperatures in...Ch. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Calculate the R-value for the following materials:...Ch. 11 - Calculate the thermal resistance due to convection...Ch. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Estimate the change in the length of a power...Ch. 11 - Calculate the change in 5 m long copper wire when...Ch. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - For Problems 11.11, 11.12, and 11.13, calculate...Ch. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55P
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- A double-angle shape, 2L7 × 4 × 5/8, is used as a tension member. The two angles are connected to a gusset plate with 7/8-inch-diameter bolts through the 7-inch legs, as shown in the figure below. A572 Grade 50 steel is used: Fy Fu = 65 ksi. Suppose that t = 5/8 in. = 50 ksi, For L7 x 4 x 5/8: Ag = 6.5 in.², x = 0.958 in. 21/2" оо 11/2" 2L7 x 4 x t a. Compute the design strength. (Express your answer to three significant figures.) ФЕРП = kips b. Compute the allowable strength. (Express your answer to three significant figures.) 'n Sit = kipsarrow_forwardI really need help on barrow_forwardWU Example 6 For the exterior transverse frame of the flat slab floor shown in figure, and by using the Direct Design Method, find: a. Longitudinal distribution of the total static moment at factored loads. b. Lateral distribution of moment at exterior panel (column and middle strip moments at exterior support) D= 6.5 kN/m² L= 5.0 kN/m² تفكر وکھل flat slap ما لا يوجد bon حامل . 3000 1000 5000 160 + 2000+ +2000+ 5000 2608 300 2000 Drop Panal السعفarrow_forward
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