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Chapter 11, Problem 11SAQ
Interpretation Introduction

Interpretation: The minimum volume of chlorine gas required for complete reaction with 7.85 g of aluminum is to be determined.

Concept Introduction: The mass of 1 mol of atoms for an element is known as its molar mass.

The ideal gas law states that the volume (V) of given amount of gas is directly proportional to the amount of gas in moles (n) and temperature of the gas (T) and is inversely proportional to the pressure of the gas (P). This is stated as:

V=RnTP

Here, R is the ideal gas constant.

The relation between atm and mm Hg is:

1 atm=760 mm Hg

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal…
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Chapter 11 Solutions

Introductory Chemistry Plus MasteringChemistry with eText - Access Card Package (5th Edition) (New Chemistry Titles from Niva Tro)

Ch. 11 - Prob. 11SAQCh. 11 - Prob. 12SAQCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - 19. Why do deep-sea divers breathe a mixture of...Ch. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 31ECh. 11 - Prob. 30ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 - 35. A snorkeler with a lung capacity of 6.3 L...Ch. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - 42. A syringe containing 1.55 mL of oxygen gas is...Ch. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - 45. A 0.12-mol sample of nitrogen gas occupies a...Ch. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - 54. A bag of potato chips contains 585 mL of air...Ch. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - An experiment shows that a 248-mL gas sample has a...Ch. 11 - Prob. 70ECh. 11 - A sample of gas has a mass of 38.8 mg. Its volume...Ch. 11 - THE IDEAL GAS LAW 72. A mixture of nitrogen and...Ch. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80ECh. 11 - Prob. 81ECh. 11 - Prob. 82ECh. 11 - Prob. 83ECh. 11 - Prob. 84ECh. 11 - Prob. 85ECh. 11 - Prob. 86ECh. 11 - Prob. 87ECh. 11 - Prob. 88ECh. 11 - Prob. 89ECh. 11 - Prob. 90ECh. 11 - 91. can be synthesized by the reaction: How many...Ch. 11 - Prob. 92ECh. 11 - 93. Nitrogen reacts with powdered aluminum...Ch. 11 - Prob. 94ECh. 11 - Prob. 95ECh. 11 - 96. Lithium reacts with nitrogen gas according to...Ch. 11 - How many grams of calcium are consumed when 156.8...Ch. 11 - Prob. 98ECh. 11 - Prob. 99ECh. 11 - Prob. 100ECh. 11 - Prob. 101ECh. 11 - Prob. 102ECh. 11 - Prob. 103ECh. 11 - Prob. 104ECh. 11 - Prob. 105ECh. 11 - Prob. 106ECh. 11 - Prob. 107ECh. 11 - 108. How many grams of oxygen are collected in a...Ch. 11 - The decomposition of a silver oxide sample forms...Ch. 11 - Prob. 110ECh. 11 - When hydrochloric acid is poured over a sample of...Ch. 11 - Prob. 112ECh. 11 - 113. Consider the reaction: If 285.5 mL of is...Ch. 11 - 114. Consider the reaction: If 88.6 L of ,...Ch. 11 - Consider the reaction for the synthesis of nitric...Ch. 11 - Consider the reaction for the production of NO2...Ch. 11 - Prob. 117ECh. 11 - Prob. 118ECh. 11 - Prob. 119ECh. 11 - Prob. 120ECh. 11 - Prob. 121ECh. 11 - Prob. 122ECh. 11 - Prob. 123ECh. 11 - Prob. 124ECh. 11 - Prob. 125ECh. 11 - Prob. 126ECh. 11 - Prob. 127ECh. 11 - 128. Aerosaol cans carry clear warnings against...
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