Introductory Chemistry Plus MasteringChemistry with eText - Access Card Package (5th Edition) (New Chemistry Titles from Niva Tro)
5th Edition
ISBN: 9780321910073
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 11, Problem 11SAQ
Interpretation Introduction
Interpretation: The minimum volume of chlorine gas required for complete reaction with
Concept Introduction: The mass of
The
Here,
The relation between
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need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
Chapter 11 Solutions
Introductory Chemistry Plus MasteringChemistry with eText - Access Card Package (5th Edition) (New Chemistry Titles from Niva Tro)
Ch. 11 - Prob. 1SAQCh. 11 - Prob. 2SAQCh. 11 - Prob. 3SAQCh. 11 - A 2.55-L gas sample in a cylinder with a freely...Ch. 11 - Prob. 5SAQCh. 11 - Prob. 6SAQCh. 11 - Prob. 7SAQCh. 11 - Prob. 8SAQCh. 11 - Prob. 9SAQCh. 11 - Prob. 10SAQ
Ch. 11 - Prob. 11SAQCh. 11 - Prob. 12SAQCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 -
19. Why do deep-sea divers breathe a mixture of...Ch. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 31ECh. 11 - Prob. 30ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 -
35. A snorkeler with a lung capacity of 6.3 L...Ch. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 -
42. A syringe containing 1.55 mL of oxygen gas is...Ch. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - 45. A 0.12-mol sample of nitrogen gas occupies a...Ch. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - 54. A bag of potato chips contains 585 mL of air...Ch. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - An experiment shows that a 248-mL gas sample has a...Ch. 11 - Prob. 70ECh. 11 - A sample of gas has a mass of 38.8 mg. Its volume...Ch. 11 - THE IDEAL GAS LAW
72. A mixture of nitrogen and...Ch. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80ECh. 11 - Prob. 81ECh. 11 - Prob. 82ECh. 11 - Prob. 83ECh. 11 - Prob. 84ECh. 11 - Prob. 85ECh. 11 - Prob. 86ECh. 11 - Prob. 87ECh. 11 - Prob. 88ECh. 11 - Prob. 89ECh. 11 - Prob. 90ECh. 11 - 91. can be synthesized by the reaction:
How many...Ch. 11 - Prob. 92ECh. 11 - 93. Nitrogen reacts with powdered aluminum...Ch. 11 - Prob. 94ECh. 11 - Prob. 95ECh. 11 -
96. Lithium reacts with nitrogen gas according to...Ch. 11 - How many grams of calcium are consumed when 156.8...Ch. 11 - Prob. 98ECh. 11 - Prob. 99ECh. 11 - Prob. 100ECh. 11 - Prob. 101ECh. 11 - Prob. 102ECh. 11 - Prob. 103ECh. 11 - Prob. 104ECh. 11 - Prob. 105ECh. 11 - Prob. 106ECh. 11 - Prob. 107ECh. 11 -
108. How many grams of oxygen are collected in a...Ch. 11 - The decomposition of a silver oxide sample forms...Ch. 11 - Prob. 110ECh. 11 - When hydrochloric acid is poured over a sample of...Ch. 11 - Prob. 112ECh. 11 -
113. Consider the reaction:
If 285.5 mL of is...Ch. 11 -
114. Consider the reaction:
If 88.6 L of ,...Ch. 11 - Consider the reaction for the synthesis of nitric...Ch. 11 - Consider the reaction for the production of NO2...Ch. 11 - Prob. 117ECh. 11 - Prob. 118ECh. 11 - Prob. 119ECh. 11 - Prob. 120ECh. 11 - Prob. 121ECh. 11 - Prob. 122ECh. 11 - Prob. 123ECh. 11 - Prob. 124ECh. 11 - Prob. 125ECh. 11 - Prob. 126ECh. 11 - Prob. 127ECh. 11 -
128. Aerosaol cans carry clear warnings against...
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- need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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