
a.
To determine:
The product of condensation reactions shown.
Introduction:
The condensation reaction is the
The base and a pentose sugar can be linked when the nitrogen (ninth position in purines or nitrogen on first position in pyrimidines) with the carbon at first position in sugar and thus forming a glycosidic bond (carbon linked with nitrogen). One molecule of water is removed from this reaction as the by-product. The reaction of nucleoside and a phosphate group results in formation of
b.
To determine:
The product of condensation reactions shown.
Introduction:
The condensation reaction is the chemical reaction, in which a larger molecule forms by the addition of two molecules and removal of a smaller molecule “generally water”.
The base and a pentose sugar can be linked when the nitrogen (ninth position in purines or nitrogen on first position in pyrimidines) with the carbon at first position in sugar and thus forming a glycosidic bond (carbon linked with nitrogen). One molecule of water is removed from this reaction as the by-product. The reaction of nucleoside and a phosphate group results in formation of nucleotide by condensation reaction.

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Chapter 11 Solutions
GENERAL ORGANIC+BIO...(LL)-W/MOD.ACCESS
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- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
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