Explanation Given Information: The length of the column, L = 20 ft The allowable load, P = 25k The value of the young modulus, E = 29000 ksi The value of maximum stress, s y = 36 ksi The thickness of the steel pipe, t = d/20 here d is the outside diameter of the steel pipe. Concept Used: d i = d − 2 ( t ) A = π 4 ( d o 2 − d i 2 ) I = π 64 ( d o 4 − d i 4 ) r = I A L c = critical length of column in ft. Then we choose different diameters d and calculate till the value of P a l l o w =P i = 1 , 2...4 n 1 i = N A i if K L i r > K L c r & n 1 i = 5 3 + 3 ( K L i r ) 8 ( K L c r ) − ( K L i r ) 3 8 ( K L c r ) 3 i f K L i r ≤ K L c r n 2 i = 23 12 if K L i r > K L c r & n 2 i = N A if K L i r ≤ K L c r σ a l l o w = σ y [ 1 n 1 i ( 1 − ( K L i r ) 2 2 ( K L c r ) 2 ) ] i f K L i r ≤ K L c r σ a l l o w = σ y [ ( K L c r ) 2 2 n 2 i ( K L i r ) 2 ] i f K L i r > K L c r P a l l o w = σ a l l o w × A Calculation: d i = d − 2 ( t ) A = π 4 ( d 2 − ( d − 2 t ) 2 ) h e r e t = d / 20 A = .14923 d 2 I = π 64 ( d 4 − ( ( d − 2 ( d / 20 ) ) 4 ) = π 64 ( d 4 − ( .9 d ) 4 ) = 0.016881 d 4 r = 0.016881 d 4 0.14932 d 2 = .33623 d ( K L r ) max = 200 , h e r e K = 1 L max = 200 × .33623 d = 67.246 d K L c / r = 2 π 2 29000 36 = 126.1 L c = ( 126

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN: 9781337093347

Author: Barry J. Goodno, James M. Gere

Publisher: Cengage Learning

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When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial …

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Chapter 11, Problem 11.9.17P

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The value of the outside diameter d for a steel pipe.

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Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…

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